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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Given linked list -- head = [4,5,1,9], which looks like following:
Example 1:
Input: head = [4,5,1,9], node = 5 Output: [4,1,9] Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:
Input: head = [4,5,1,9], node = 1 Output: [4,5,9] Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
Note:
- The linked list will have at least two elements.
- All of the nodes' values will be unique.
- The given node will not be the tail and it will always be a valid node of the linked list.
- Do not return anything from your function.
请编写一个函数，使其可以删除某个链表中给定的（非末尾）节点，你将只被给定要求被删除的节点。
现有一个链表 -- head = [4,5,1,9]，它可以表示为:
4 -> 5 -> 1 -> 9
示例 1:
输入: head = [4,5,1,9], node = 5 输出: [4,1,9] 解释: 给定你链表中值为 5 的第二个节点，那么在调用了你的函数之后，该链表应变为 4 -> 1 -> 9.
示例 2:
输入: head = [4,5,1,9], node = 1 输出: [4,5,9] 解释: 给定你链表中值为 1 的第三个节点，那么在调用了你的函数之后，该链表应变为 4 -> 5 -> 9.
说明:
- 链表至少包含两个节点。
- 链表中所有节点的值都是唯一的。
- 给定的节点为非末尾节点并且一定是链表中的一个有效节点。
- 不要从你的函数中返回任何结果。
0ms
1 class Solution { 2 public void deleteNode(ListNode node) { 3 node.val=node.next.val; 4 node.next=node.next.next; 5 } 6 }
34180 kb
1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { val = x; } 7 * } 8 */ 9 class Solution { 10 public void deleteNode(ListNode node) { 11 12 int temp; 13 temp = node.val; 14 node.val = node.next.val; 15 node.next.val = temp; 16 17 node.next = node.next.next; 18 19 } 20 }