SQL server 2005新增的几个函数,分别是row_number( )、rank( )、,dense_rank( )、ntile( )下面以实例分别简单讲解。
1.row_number( )
先来点数据,先建个表
CREATE TABLE Person(
FirstName VARCHAR(10),
Age INT,
Gender CHAR(1))
INSERT INTO Person VALUES ('Ted',23,'M')
INSERT INTO Person VALUES ('John',40,'M')
INSERT INTO Person VALUES ('George',6,'M')
INSERT INTO Person VALUES ('Mary',11,'F')
INSERT INTO Person VALUES ('Sam',17,'M')
INSERT INTO Person VALUES ('Doris',6,'F')
INSERT INTO Person VALUES ('Frank',38,'M')
INSERT INTO Person VALUES ('Larry',5,'M')
INSERT INTO Person VALUES ('Sue',29,'F')
INSERT INTO Person VALUES ('Sherry',11,'F')
INSERT INTO Person VALUES ('Marty',23,'F')
FirstName,
Age
FROM Person
出现的数据如下
Row Number by Age FirstName Age
-------------------------- ---------- --------
1 Larry 5
2 Doris 6
3 George 6
4 Mary 11
5 Sherry 11
6 Sam 17
7 Ted 23
8 Marty 23
9 Sue 29
10 Frank 38
11 John 40
可以观察到,是根据年龄升序排列了，并且row_number()是给出了序列号了,这个序列号被重命名为Row Number by Age,
与sql server2000对比:
如果在sql server2000中实现相对麻烦一些，我们可以利用IDENTITY()函数实现，但IDENTITY()函数只能用在sql server2000临时表中，因此需要将数据检索到临时表里。
select identity(int,1,1) as [Row Number by Age],FirstName,Age into #A from Person order by Age
select * from #A
drop table #a
如果不想按年龄排序,可以这样写
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS [Row Number by Record Set], FirstName, Age FROM Person
另外一个例子
SELECT ROW_NUMBER() OVER (PARTITION BY Gender ORDER BY Age) AS [Partition by Gender], FirstName, Age, Gender FROM Person
Partition by Gender FirstName Age Gender -------------------- ---------- ----------- ------ 1 Doris 6 F 2 Mary 11 F 3 Sherry 11 F 4 Sue 29 F 1 Larry 5 M 2 George 6 M 3 Sam 17 M 4 Ted 23 M 5 Marty 23 M 6 Frank 38 M 7 John 40 M注意,姓名M开始,序号又从1,2,3开始了
2.RANK( )函数
先看例子
SELECT RANK() OVER (ORDER BY Age) AS [Rank by Age], FirstName, Age FROM Person
输出如下:
Rank by Age FirstName Age -------------------- ---------- ----------- 1 Larry 5 2 Doris 6 2 George 6 4 Mary 11 4 Sherry 11 6 Sam 17 7 Ted 23 7 Marty 23 9 Sue 29 10 Frank 38 11 John 40
看到了么,同年岭的话,将有相同的顺序,顺序成1,2,2,4了。
与sql server2000对比:
出现了RANK()函数实在是方便,在sql server2000里实现排序并列的问题麻烦很多。
select [Rank by Age]=isnull((select count(*) from person where Age>A.Age),0)+1,FirstName,Age from Person A order by [Rank by Age]
SELECT RANK() OVER(PARTITION BY Gender ORDER BY Age) AS [Partition by Gender],
FirstName, Age, Gender FROM Person输出为
Partition by Gender FirstName Age Gender -------------------- ---------- ----------- ------ 1 Doris 6 F 2 Mary 11 F 2 Sherry 11 F 4 Sue 29 F 1 Larry 5 M 2 George 6 M 3 Sam 17 M 4 Ted 23 M 4 Marty 23 M 6 Frank 38 M 7 John 40 M
可以看到,按性别分组了,每个性别分组里,继续是用了rank( )函数
3.DENSE_RANK(
)函数
SELECT DENSE_RANK() OVER
(ORDER BY Age) AS [Dense Rank by Age],
FirstName,
Age
FROM Person
输出结果为:
Dense Rank by Age
FirstName Age
-------------------- ----------
-----------
1 Larry
5
2 Doris 6
2
George 6
3 Mary
11
3 Sherry
11
4 Sam
17
5 Ted
23
5 Marty
23
6 Sue
29
7 Frank
38
8 John
40
看到了么,和rank函数区别是,顺序始终是连续的,Doris
和George同年,都是排第2位,但之后的mary不象rank函数那样排第4,而是排第3位了
4.ntile(
)函数
SELECT FirstName,
Age,
NTILE(3) OVER (ORDER BY Age) AS [Age
Groups]
FROM Person
输出结果：
FirstName Age Age Groups
----------
----------- --------------------
Larry 5
1
Doris 6 1
George
6 1
Mary 11
1
Sherry 11 2
Sam
17 2
Ted 23
2
Marty 23 2
Sue
29 3
Frank 38
3
John 40
3
这个函数按照ntile(n)中的N,把记录强制分成多少段,11条记录现在分成3段了,lary到mary是第1段,sherry到maty是第2段,sue到john是第3段了