九度OJ 1439：Least Common Multiple

题目描述：

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

输入：

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

输出：

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

样例输入：

2
3 5 7 15
6 4 10296 936 1287 792 1

样例输出：

105
10296

#include <cstdio>
//5 7 15
// 1  1  5
// 35 105 15
int gcd(int n,int m){
    return m == 0 ? n: gcd(m,n%m);
}
int main(){
    /*
    int n,m;
    while(scanf("%d%d",&n,&m) != EOF){
        printf("%d
",gcd(n,m));
    }*/
    int n,m;
    int b,temp;
    scanf("%d",&n);
    while(n--){
        scanf("%d",&m);
        temp = 1;
        for(int i = 0;i < m;i++){
            scanf("%d",&b);
            temp = b/gcd(temp,b)*temp;
            //a = temp;
        }
        printf("%d
",temp);
    }
}