打开 Program.cs 代码文件,这里是程序的入口点,如下:
static void Main() { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Application.Run(new frMain()); }
经过以下修改,就可以实现同一个进程只能打开一次的效果:
static void Main() { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); //1.这里判定是否已经有实例在运行 //只运行一个实例 Process instance = RunningInstance(); if (instance == null) { //1.1 没有实例在运行 Application.Run(new FrMain()); } else { //1.2 已经有一个实例在运行 HandleRunningInstance(instance); } } //2.在进程中查找是否已经有实例在运行 private static Process RunningInstance() { Process current = Process.GetCurrentProcess(); Process[] processes = Process.GetProcessesByName(current.ProcessName); //遍历与当前进程名称相同的进程列表 foreach (Process process in processes) { //如果实例已经存在则忽略当前进程 if (process.Id != current.Id) { //保证要打开的进程同已经存在的进程来自同一文件路径 if (Assembly.GetExecutingAssembly().Location.Replace("/", "\") == current.MainModule.FileName) { //返回已经存在的进程 return process; } } } return null; } //3.已经有了就把它激活,并将其窗口放置最前端 private static void HandleRunningInstance(Process instance) { ShowWindowAsync(instance.MainWindowHandle, 1); //调用api函数,正常显示窗口 SetForegroundWindow(instance.MainWindowHandle); //将窗口放置最前端 }
[DllImport("User32.dll")] private static extern bool ShowWindowAsync(System.IntPtr hWnd, int cmdShow); [DllImport("User32.dll")] private static extern bool SetForegroundWindow(System.IntPtr hWnd);