• 算法(Algorithms)第4版 练习 1.3.42


    After copy
    Left on Stack r: be to not or be to 
    Left on Stack copy: be to not or be to 
    After r pop
    Left on Stack r: to not or be to 
    Left on Stack copy: be to not or be to 
    //1.3.42
            Stack<String> r = new Stack<String>(copy);
            StdOut.println("After copy");
            StdOut.print("Left on Stack r: ");
            for (String s : r) {
                StdOut.print(s + " ");
            }
            StdOut.println();
            StdOut.print("Left on Stack copy: ");
            for (String s : copy) {
                StdOut.print(s + " ");
            }
            StdOut.println();
            
            r.pop();
            StdOut.println("After r pop");
            StdOut.print("Left on Stack r: ");
            for (String s : r) {
                StdOut.print(s + " ");
            }
            StdOut.println();
            StdOut.print("Left on Stack copy: ");
            for (String s : copy) {
                StdOut.print(s + " ");
            }
            StdOut.println();
        //1.3.42
        public Stack(Stack<Item> stack) {
            
            first = null;
            n = 0;
            
            Stack<Item> temp = new Stack<Item>();
            
            for(Item item : stack) {
                temp.push(item);
            }
            for(Item item : temp) {
                this.push(item);
            }
            
        }
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  • 原文地址:https://www.cnblogs.com/songdechiu/p/6522887.html
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