C--汇编对应查看方法

一：c语言编写简单函数(function_example.c)

#include <stdio.h>
int static add(int a, int b)
{
    return a+b;
}

int main()
{
    int x = 5;
    int y = 10;
    int u = add(x, y);
}

二：gcc编译

$ gcc -g -c function_example.c

三：objdump查看C语言和对应汇编

$ objdump -d -M intel -S function_example.o
function_example.o:     file format elf64-x86-64


Disassembly of section .text:

0000000000000000 <add>:
#include <stdio.h>

int static add(int a, int b)
{
   0:	55                   	push   rbp
   1:	48 89 e5             	mov    rbp,rsp
   4:	89 7d fc             	mov    DWORD PTR [rbp-0x4],edi
   7:	89 75 f8             	mov    DWORD PTR [rbp-0x8],esi
    return a+b;
   a:	8b 55 fc             	mov    edx,DWORD PTR [rbp-0x4]
   d:	8b 45 f8             	mov    eax,DWORD PTR [rbp-0x8]
  10:	01 d0                	add    eax,edx
}
  12:	5d                   	pop    rbp
  13:	c3                   	ret    

0000000000000014 <main>:

int main()
{
  14:	55                   	push   rbp
  15:	48 89 e5             	mov    rbp,rsp
  18:	48 83 ec 10          	sub    rsp,0x10
    int x = 5;
  1c:	c7 45 fc 05 00 00 00 	mov    DWORD PTR [rbp-0x4],0x5
    int y = 10;
  23:	c7 45 f8 0a 00 00 00 	mov    DWORD PTR [rbp-0x8],0xa
    int u = add(x, y);
  2a:	8b 55 f8             	mov    edx,DWORD PTR [rbp-0x8]
  2d:	8b 45 fc             	mov    eax,DWORD PTR [rbp-0x4]
  30:	89 d6                	mov    esi,edx
  32:	89 c7                	mov    edi,eax
  34:	e8 c7 ff ff ff       	call   0 <add>
  39:	89 45 f4             	mov    DWORD PTR [rbp-0xc],eax
  3c:	b8 00 00 00 00       	mov    eax,0x0
}
  41:	c9                   	leave  
  42:	c3                   	ret