题目链接
https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/
题目原文
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
题目大意
给定一个已经排好序的数组,构建一个高度平衡的二叉树
解题思路
在数组中找到根节点,然后递归构建左右子树
代码
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def sortedArrayToBST(self, nums):
"""
:type nums: List[int]
:rtype: TreeNode
"""
l = len(nums)
if l == 0:
return None
if l == 1:
return TreeNode(nums[0])
root = TreeNode(nums[l // 2])
root.left = self.sortedArrayToBST(nums[:l // 2])
root.right = self.sortedArrayToBST(nums[l // 2 + 1:])
return root