• 用python3破解wingIDE


     值得注意的是,python2的整除/在python3中变成了//,sha方法细化成了sha1和sha256,所以破解文件需要更改加密方式和整除部分的编码方式,经过修改后,这个文件可以完美演算出破解码,你懂得

    import hashlib
    import string
    BASE2 = '01'
    BASE10 = '0123456789'
    BASE16 = '0123456789ABCDEF'
    BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
    BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
    BASEMAX = string.printable
    def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
        """ converts a "number" between two bases of arbitrary digits
        
        The input number is assumed to be a string of digits from the
        fromdigits string (which is in order of smallest to largest
        digit). The return value is a string of elements from todigits
        (ordered in the same way). The input and output bases are
        determined from the lengths of the digit strings. Negative 
        signs are passed through.
        
        decimal to binary
        >>> baseconvert(555,BASE10,BASE2)
        '1000101011'
        
        binary to decimal
        >>> baseconvert('1000101011',BASE2,BASE10)
        '555'
        
        integer interpreted as binary and converted to decimal (!)
        >>> baseconvert(1000101011,BASE2,BASE10)
        '555'
        
        base10 to base4
        >>> baseconvert(99,BASE10,"0123")
        '1203'
        
        base4 to base5 (with alphabetic digits)
        >>> baseconvert(1203,"0123","abcde")
        'dee'
        
        base5, alpha digits back to base 10
        >>> baseconvert('dee',"abcde",BASE10)
        '99'
        
        decimal to a base that uses A-Z0-9a-z for its digits
        >>> baseconvert(257938572394L,BASE10,BASE62)
        'E78Lxik'
        
        ..convert back
        >>> baseconvert('E78Lxik',BASE62,BASE10)
        '257938572394'
        
        binary to a base with words for digits (the function cannot convert this back)
        >>> baseconvert('1101',BASE2,('Zero','One'))
        'OneOneZeroOne'
        
        """
        if not ignore_negative and str(number)[0] == '-':
            number = str(number)[1:]
            neg = 1
        else:
            neg = 0
        x = 0
        for digit in str(number):
            x = x * len(fromdigits) + fromdigits.index(digit)
    
        res = ''
        while x > 0:
            digit = x % len(todigits)
            res = todigits[int(digit)] + res
            x //= len(todigits)
    
        if neg:
            res = '-' + res
        return res
    
    def SHAToBase30(digest):
        """Convert from a hexdigest form SHA hash into a more compact and
        ergonomic BASE30 representation.  This results in a 17 'digit' 
        number."""
        tdigest = ''.join([ c for i, c in enumerate(str(digest)) if int(i) // 2 * 2 == int(i) ])
        result = BaseConvert(tdigest, BASE16, BASE30)
        while len(result) < 17:
            result = '1' + result
    
        return result
    def AddHyphens(code):
        """Insert hyphens into given license id or activation request to
        make it easier to read"""
        return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:]
    
    LicenseID='CN123-12345-12345-12345'
    LicenseID='ENX27-HWM6G-XYVFA-165PG'
    #Copy the Request Code from the dialog
    RequestCode='RW52X-G93T8-R2927-YJYFX'
    hasher = hashlib.sha1()
    hasher.update(bytes(RequestCode, 'ascii'))
    hasher.update(bytes(LicenseID, 'ascii'))
    digest = hasher.hexdigest().upper()
    lichash = RequestCode[:3] + SHAToBase30(digest)
    lichash=AddHyphens(lichash)
    #Calculate the Activation Code
    data=[7,123,23,87]
    tmp=0
    realcode=''
    for i in data:
        for j in lichash:
            tmp=(tmp*i+ord(j))&0xFFFFF
        realcode+=format(tmp,'=05X')
        tmp=0
    
    act30=BaseConvert(realcode,BASE16,BASE30)
    while len(act30) < 17:
        act30 = '1' + act30
    act30='AXX'+act30
    act30=AddHyphens(act30)
    print ("The Activation Code is: "+act30)

     作为比较,把python2的破解代码放在下方:

    import sha
    import string
    BASE2 = '01'
    BASE10 = '0123456789'
    BASE16 = '0123456789ABCDEF'
    BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
    BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
    BASEMAX = string.printable
    def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
        """ converts a "number" between two bases of arbitrary digits
        
        The input number is assumed to be a string of digits from the
        fromdigits string (which is in order of smallest to largest
        digit). The return value is a string of elements from todigits
        (ordered in the same way). The input and output bases are
        determined from the lengths of the digit strings. Negative 
        signs are passed through.
        
        decimal to binary
        >>> baseconvert(555,BASE10,BASE2)
        '1000101011'
        
        binary to decimal
        >>> baseconvert('1000101011',BASE2,BASE10)
        '555'
        
        integer interpreted as binary and converted to decimal (!)
        >>> baseconvert(1000101011,BASE2,BASE10)
        '555'
        
        base10 to base4
        >>> baseconvert(99,BASE10,"0123")
        '1203'
        
        base4 to base5 (with alphabetic digits)
        >>> baseconvert(1203,"0123","abcde")
        'dee'
        
        base5, alpha digits back to base 10
        >>> baseconvert('dee',"abcde",BASE10)
        '99'
        
        decimal to a base that uses A-Z0-9a-z for its digits
        >>> baseconvert(257938572394L,BASE10,BASE62)
        'E78Lxik'
        
        ..convert back
        >>> baseconvert('E78Lxik',BASE62,BASE10)
        '257938572394'
        
        binary to a base with words for digits (the function cannot convert this back)
        >>> baseconvert('1101',BASE2,('Zero','One'))
        'OneOneZeroOne'
        
        """
        if not ignore_negative and str(number)[0] == '-':
            number = str(number)[1:]
            neg = 1
        else:
            neg = 0
        x = long(0)
        for digit in str(number):
            x = x * len(fromdigits) + fromdigits.index(digit)
    
        res = ''
        while x > 0:
            digit = x % len(todigits)
            res = todigits[digit] + res
            x /= len(todigits)
    
        if neg:
            res = '-' + res
        return res
    
    def SHAToBase30(digest):
        """Convert from a hexdigest form SHA hash into a more compact and
        ergonomic BASE30 representation.  This results in a 17 'digit' 
        number."""
        tdigest = ''.join([ c for i, c in enumerate(digest) if i / 2 * 2 == i ])
        print 'tdigest',tdigest
        result = BaseConvert(tdigest, BASE16, BASE30)
        while len(result) < 17:
            result = '1' + result
    
        return result
    def AddHyphens(code):
        """Insert hyphens into given license id or activation request to
        make it easier to read"""
        return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:]
    
    LicenseID='CN123-12345-12345-12345'
    
    LicenseID='ENX27-HWM6G-XYVFA-165PG'
    #Copy the Request Code from the dialog
    RequestCode='RW52X-G93T8-R2927-YJYFX'
    hasher = sha.new()
    
    hasher.update(RequestCode)
    hasher.update(LicenseID)
    digest = hasher.hexdigest().upper()
    lichash = RequestCode[:3] + SHAToBase30(digest)
    #print RequestCode[:3] ,SHAToBase30(digest)
    lichash=AddHyphens(lichash)
    #Calculate the Activation Code
    data=[7,123,23,87]
    tmp=0
    realcode=''
    for i in data:
        for j in lichash:
            tmp=(tmp*i+ord(j))&0xFFFFF
        realcode+=format(tmp,'=05X')
        tmp=0
    
    act30=BaseConvert(realcode,BASE16,BASE30)
    while len(act30) < 17:
        act30 = '1' + act30
    act30='AXX'+act30
    act30=AddHyphens(act30)
    print ("The Activation Code is: "+act30)
  • 相关阅读:
    C 语言指针小结
    NOIP2012 复赛考生须知!
    2012 NOIP 初赛复习指导
    16元的纸币
    记一次社会化的钓鱼攻击
    福州大学ACM代表队获36届ACMICPC全球总决赛第18名
    福州教育相关教育资源介绍
    世界末日:科普很重要啊~~~
    201212信息学奥林匹克竞赛,新生招募
    模拟人脑:这个事儿,闹大了
  • 原文地址:https://www.cnblogs.com/slqt/p/5355069.html
Copyright © 2020-2023  润新知