题目链接
/*
Name:NYOJ-130-相同的雪花
Copyright:
Author:
Date: 2018/4/14 15:13:39
Description:
将雪花各个分支上的值加起来,hash
*/
#include <iostream>
#include <vector>
#include <cstdio>
#include <cstring>
using namespace std;
const int MAXN = 1e5+10;
int snowflakes[MAXN][7];
vector<int> snow[5001];//hash
int Like(int x,int y)//判断两片雪花是否相同
{
for(int i=0;i<6;i++)
{
if((snowflakes[x][0]==snowflakes[y][i]&&snowflakes[x][1]==snowflakes[y][(i+1)%6]&&snowflakes[x][2]==snowflakes[y][(i+2)%6]&&snowflakes[x][3]==snowflakes[y][(i+3)%6]&&snowflakes[x][4]==snowflakes[y][(i+4)%6]&&snowflakes[x][5]==snowflakes[y][(i+5)%6])///顺时针方向判断两个雪花是否相同
||(snowflakes[x][0]==snowflakes[y][(i+5)%6]&&snowflakes[x][1]==snowflakes[y][(i+4)%6]&&snowflakes[x][2]==snowflakes[y][(i+3)%6]&&snowflakes[x][3]==snowflakes[y][(i+2)%6]&&snowflakes[x][4]==snowflakes[y][(i+1)%6]&&snowflakes[x][5]==snowflakes[y][i]))///逆时针方向判断两个雪花是否相同
return 1;
}
return 0;
}
int main()
{
// freopen("in.txt", "r", stdin);
int t;
cin>>t;
while (t--) {
memset(snow, 0, sizeof(snow));
int n;
cin>>n;
for (int i=0; i<n; i++) {
int sum = 0;
for (int j=0; j<6; j++) {
int tmp;
cin>>tmp;
snowflakes[i][j] = tmp;
sum += tmp;
}
sum = sum % 5000;//防止越界
snow[sum].push_back(i);
}
int flag = 0 ;
for (int i=0; i<5000; i++) {
if (flag) break;
if (snow[i].size() < 2) continue;
for (int j=0; j<snow[i].size()-1; j++) {
for (int k=j+1; k<snow[i].size(); k++) {
if (Like(snow[i][j], snow[i][k])) {
flag = 1;
break;
}
}
}
}
if(flag)printf("Twin snowflakes found.
");
else printf("No two snowflakes are alike.
");
}
return 0;
}