• 详细介绍C++STL:unordered_map


    不得不提一下,hash_map未加入在C++11标准中。

    在VC中编译: 

    1 #include <hash_map>
    2 using namespace stdext;
    3 hash_map<int ,int> myhash;

     在GCC中编译:

    1 #include <ext/hash_map>
    2 using namespace __gnu_cxx;
    3 hash_map<int ,int> myhash;

    既如此,还是用unordered_map吧!

    C++ 11标准中加入了unordered系列的容器。unordered_map记录元素的hash值,根据hash值判断元素是否相同。map相当于java中的TreeMap,unordered_map相当于HashMap。无论从查找、插入上来说,unordered_map的效率都优于hash_map,更优于map;而空间复杂度方面,hash_map最低,unordered_map次之,map最大。

    unordered_map与map的对比:

      存储时是根据key的hash值判断元素是否相同,即unordered_map内部元素是无序的,而map中的元素是按照二叉搜索树存储(用红黑树实现),进行中序遍历会得到有序遍历。所以使用时map的key需要定义operator<。而unordered_map需要定义hash_value函数并且重载operator==。但是很多系统内置的数据类型都自带这些。

      总结:结构体用map重载<运算符,结构体用unordered_map重载==运算符。

    unordered_map与hash_map对比:

      unordered_map原来属于boost分支和std::tr1中,而hash_map属于非标准容器。
      unordered_map感觉速度和hash_map差不多,但是支持string做key,也可以使用复杂的对象作为key。
      unordered_map编译时gxx需要添加编译选项:--std=c++11

    unordered_map模板: 

    1 template < class Key,                                    // unordered_map::key_type
    2            class T,                                      // unordered_map::mapped_type
    3            class Hash = hash<Key>,                       // unordered_map::hasher
    4            class Pred = equal_to<Key>,                   // unordered_map::key_equal
    5            class Alloc = allocator< pair<const Key,T> >  // unordered_map::allocator_type
    6            > class unordered_map;

     迭代器:

    unordered_map的迭代器是一个指针,指向这个元素,通过迭代器来取得它的值。

    1 unordered_map<Key,T>::iterator it;
    2 (*it).first;             // the key value (of type Key)
    3 (*it).second;            // the mapped value (of type T)
    4 (*it);                   // the "element value" (of type pair<const Key,T>) 

    它的键值分别是迭代器的first和second属性。 

    1 it->first;               // same as (*it).first   (the key value)
    2 it->second;              // same as (*it).second  (the mapped value) 

    成员函数:

    =================迭代器========================= 
    begin   返回指向容器起始位置的迭代器(iterator) 
    end      返回指向容器末尾位置的迭代器 
    cbegin    返回指向容器起始位置的常迭代器(const_iterator) 
    cend    返回指向容器末尾位置的常迭代器 
    =================Capacity================ 
    size     返回有效元素个数 
    max_size  返回 unordered_map 支持的最大元素个数 
    empty        判断是否为空 
    =================元素访问================= 
    operator[]       访问元素 
    at         访问元素 
    =================元素修改================= 
    insert    插入元素 
    erase   删除元素 
    swap    交换内容 
    clear     清空内容 
    emplace  构造及插入一个元素 
    emplace_hint 按提示构造及插入一个元素 
    ================操作========================= 
    find       通过给定主键查找元素,没找到:返回unordered_map::end
    count      返回匹配给定主键的元素的个数 
    equal_range   返回值匹配给定搜索值的元素组成的范围 
    ================Buckets====================== 
    bucket_count    返回槽(Bucket)数 
    max_bucket_count    返回最大槽数 
    bucket_size       返回槽大小 
    bucket       返回元素所在槽的序号 
    load_factor     返回载入因子,即一个元素槽(Bucket)的最大元素数 
    max_load_factor    返回或设置最大载入因子 
    rehash       设置槽数 
    reserve        请求改变容器容量

     插入元素示例:

     1 // unordered_map::insert
     2 #include <iostream>
     3 #include <string>
     4 #include <unordered_map>
     5 using namespace std;
     6 
     7 void display(unordered_map<string,double> myrecipe,string str)
     8 {
     9     cout << str << endl;
    10     for (auto& x: myrecipe)
    11         cout << x.first << ": " << x.second << endl;
    12     cout << endl;
    13 }
    14 
    15 int main ()
    16 {
    17     unordered_map<string,double>
    18     myrecipe,
    19     mypantry = {{"milk",2.0},{"flour",1.5}};
    20 
    21     /****************插入*****************/
    22     pair<string,double> myshopping ("baking powder",0.3);
    23     myrecipe.insert (myshopping);                        // 复制插入
    24     myrecipe.insert (make_pair<string,double>("eggs",6.0)); // 移动插入
    25     myrecipe.insert (mypantry.begin(), mypantry.end());  // 范围插入
    26     myrecipe.insert ({{"sugar",0.8},{"salt",0.1}});    // 初始化数组插入(可以用二维一次插入多个元素,也可以用一维插入一个元素)
    27     myrecipe["coffee"] = 10.0;  //数组形式插入
    28 
    29     display(myrecipe,"myrecipe contains:");
    30 
    31     /****************查找*****************/
    32     unordered_map<string,double>::const_iterator got = myrecipe.find ("coffee");
    33 
    34     if ( got == myrecipe.end() )
    35         cout << "not found";
    36     else
    37         cout << "found "<<got->first << " is " << got->second<<"
    
    ";
    38     /****************修改*****************/
    39     myrecipe.at("coffee") = 9.0;
    40     myrecipe["milk"] = 3.0;
    41     display(myrecipe,"After modify myrecipe contains:");
    42 
    43 
    44     /****************擦除*****************/
    45     myrecipe.erase(myrecipe.begin());  //通过位置
    46     myrecipe.erase("milk");    //通过key
    47     display(myrecipe,"After erase myrecipe contains:");
    48 
    49     /****************交换*****************/
    50     myrecipe.swap(mypantry);
    51     display(myrecipe,"After swap with mypantry, myrecipe contains:");
    52 
    53     /****************清空*****************/
    54     myrecipe.clear();
    55     display(myrecipe,"After clear, myrecipe contains:");
    56     return 0;
    57 }
    58 /*
    59 myrecipe contains:
    60 salt: 0.1
    61 milk: 2
    62 flour: 1.5
    63 coffee: 10
    64 eggs: 6
    65 sugar: 0.8
    66 baking powder: 0.3
    67 
    68 found coffee is 10
    69 
    70 After modify myrecipe contains:
    71 salt: 0.1
    72 milk: 3
    73 flour: 1.5
    74 coffee: 9
    75 eggs: 6
    76 sugar: 0.8
    77 baking powder: 0.3
    78 
    79 After erase myrecipe contains:
    80 flour: 1.5
    81 coffee: 9
    82 eggs: 6
    83 sugar: 0.8
    84 baking powder: 0.3
    85 
    86 After swap with mypantry, myrecipe contains:
    87 flour: 1.5
    88 milk: 2
    89 
    90 After clear, myrecipe contains:
    91 */

    遍历示例:

     1 // unordered_map::bucket_count
     2 #include <iostream>
     3 #include <string>
     4 #include <unordered_map>
     5 using namespace std;
     6 
     7 int main ()
     8 {
     9     unordered_map<string,string> mymap =
    10     {
    11         {"house","maison"},
    12         {"apple","pomme"},
    13         {"tree","arbre"},
    14         {"book","livre"},
    15         {"door","porte"},
    16         {"grapefruit","pamplemousse"}
    17     };
    18     /************begin和end迭代器***************/
    19     cout << "mymap contains:";
    20     for ( auto it = mymap.begin(); it != mymap.end(); ++it )
    21         cout << " " << it->first << ":" << it->second;
    22     cout << endl;
    23     /************bucket操作***************/
    24      unsigned n = mymap.bucket_count();
    25 
    26     cout << "mymap has " << n << " buckets.
    ";
    27 
    28     for (unsigned i=0; i<n; ++i)
    29     {
    30         cout << "bucket #" << i << "'s size:"<<mymap.bucket_size(i)<<" contains: ";
    31         for (auto it = mymap.begin(i); it!=mymap.end(i); ++it)
    32             cout << "[" << it->first << ":" << it->second << "] ";
    33         cout << "
    ";
    34     }
    35 
    36     cout <<"
    key:'apple' is in bucket #" << mymap.bucket("apple") <<endl;
    37     cout <<"
    key:'computer' is in bucket #" << mymap.bucket("computer") <<endl;
    38 
    39     return 0;
    40 }
    41 /*
    42 mymap contains: door:porte grapefruit:pamplemousse tree:arbre apple:pomme book:livre house:maison
    43 mymap has 7 buckets.
    44 bucket #0's size:2 contains: [book:livre] [house:maison]
    45 bucket #1's size:0 contains:
    46 bucket #2's size:0 contains:
    47 bucket #3's size:2 contains: [grapefruit:pamplemousse] [tree:arbre]
    48 bucket #4's size:0 contains:
    49 bucket #5's size:1 contains: [apple:pomme]
    50 bucket #6's size:1 contains: [door:porte]
    51 
    52 key:'apple' is in bucket #5
    53 
    54 key:'computer' is in bucket #6
    55 */
  • 相关阅读:
    爬虫 xpath
    Mongo 基础命令
    大数据 Spark 连接外部资源
    大数据 Spark 异常
    大数据 Spark 安装
    python 对象克隆
    一个Vue表单提交防抖的实用例子
    一个防抖和节流的实用例子
    前端面试100问(1-10)
    每日技术:encodeURI,encodeURIComponent,toFixed
  • 原文地址:https://www.cnblogs.com/slothrbk/p/8823092.html
Copyright © 2020-2023  润新知