• UVa 1449 Dominating Patterns


    方法:AC自动机

    题意比较明显,用ac 自动机。陷阱是可能会出现重复的string。

    code:

      1 #include <cstdio>
      2 #include <cstring>
      3 #include <algorithm>
      4 #include <iostream>
      5 #include <string>
      6 #include <vector>
      7 #include <stack>
      8 #include <bitset>
      9 #include <cstdlib>
     10 #include <cmath>
     11 #include <set>
     12 #include <list>
     13 #include <deque>
     14 #include <map>
     15 #include <queue>
     16 #include <fstream>
     17 #include <cassert>
     18 #include <unordered_map>
     19 #include <unordered_set>
     20 #include <cmath>
     21 #include <sstream>
     22 #include <time.h>
     23 #include <complex>
     24 #include <iomanip>
     25 #define Max(a,b) ((a)>(b)?(a):(b))
     26 #define Min(a,b) ((a)<(b)?(a):(b))
     27 #define FOR(a,b,c) for (ll (a)=(b);(a)<(c);++(a))
     28 #define FORN(a,b,c) for (ll (a)=(b);(a)<=(c);++(a))
     29 #define DFOR(a,b,c) for (ll (a)=(b);(a)>=(c);--(a))
     30 #define FORSQ(a,b,c) for (ll (a)=(b);(a)*(a)<=(c);++(a))
     31 #define FORC(a,b,c) for (char (a)=(b);(a)<=(c);++(a))
     32 #define FOREACH(a,b) for (auto &(a) : (b))
     33 #define rep(i,n) FOR(i,0,n)
     34 #define repn(i,n) FORN(i,1,n)
     35 #define drep(i,n) DFOR(i,n-1,0)
     36 #define drepn(i,n) DFOR(i,n,1)
     37 #define MAX(a,b) a = Max(a,b)
     38 #define MIN(a,b) a = Min(a,b)
     39 #define SQR(x) ((LL)(x) * (x))
     40 #define Reset(a,b) memset(a,b,sizeof(a))
     41 #define fi first
     42 #define se second
     43 #define mp make_pair
     44 #define pb push_back
     45 #define all(v) v.begin(),v.end()
     46 #define ALLA(arr,sz) arr,arr+sz
     47 #define SIZE(v) (int)v.size()
     48 #define SORT(v) sort(all(v))
     49 #define REVERSE(v) reverse(ALL(v))
     50 #define SORTA(arr,sz) sort(ALLA(arr,sz))
     51 #define REVERSEA(arr,sz) reverse(ALLA(arr,sz))
     52 #define PERMUTE next_permutation
     53 #define TC(t) while(t--)
     54 #define forever for(;;)
     55 #define PINF 1000000000000
     56 #define newline '
    '
     57 
     58 #define test if(1)if(0)cerr
     59 using namespace std;
     60 using namespace std;
     61 typedef vector<int> vi;
     62 typedef vector<vi> vvi;
     63 typedef pair<int,int> ii;
     64 typedef pair<double,double> dd;
     65 typedef pair<char,char> cc;
     66 typedef vector<ii> vii;
     67 typedef long long ll;
     68 typedef unsigned long long ull;
     69 typedef pair<ll, ll> l4;
     70 const double pi = acos(-1.0);
     71 
     72 
     73 const int MAXNODE = 11000+5;
     74 const int SIGMA_SIZE = 26;
     75 
     76 
     77 int n;
     78 string text, input[151];
     79 map<string, int> ms;
     80 
     81 
     82 inline int idx(char c) { return c-'a'; }
     83 int cnt[151];
     84 struct AC
     85 {
     86     int g[MAXNODE][SIGMA_SIZE], f[MAXNODE], val[MAXNODE], last[MAXNODE];
     87     int sz;
     88     int newnode()
     89     {
     90         memset(g[sz], 0, sizeof(g[sz]));
     91         val[sz] = 0;
     92         return sz++;
     93     }
     94     void init()
     95     {
     96         sz = 0; newnode();
     97     }
     98     void insert(const string &str, int v)
     99     {
    100         int u = 0, n = str.length();
    101         for (int i = 0; i < n; ++i)
    102         {
    103             int c = idx(str[i]);
    104             if (!g[u][c]) g[u][c] = newnode();
    105             u = g[u][c];
    106         }
    107         val[u] = v;
    108     }
    109     void print(int j)
    110     {
    111         if (j)
    112         {
    113             ++cnt[val[j]];
    114 
    115             // operation
    116             print(last[j]);
    117         }
    118     }
    119     void find(const string &str)
    120     {
    121         int n = str.length(), j = 0;
    122         for (int i = 0; i < n; ++i)
    123         {
    124             int c = idx(str[i]);
    125             j = g[j][c];
    126 
    127             if (val[j]) print(j);
    128             else if (last[j]) print(last[j]);
    129         }
    130     }
    131     void get_fail()
    132     {
    133         queue<int> q; f[0] = 0; last[0] = 0;
    134         for (int c = 0; c < SIGMA_SIZE; ++c)
    135         {
    136             int u = g[0][c];
    137             if (u) { f[u] = 0; q.push(u); last[u] = 0; }
    138         }
    139         while (!q.empty())
    140         {
    141             int r = q.front();  q.pop();
    142             for (int c = 0; c < SIGMA_SIZE; ++c)
    143             {
    144                 int u = g[r][c];
    145                 if (!u) { g[r][c] = g[f[r]][c]; continue; }
    146                 q.push(u);
    147                 int v = f[r];
    148                 while (v && !g[v][c]) v = f[v];
    149                 f[u] = g[v][c];
    150                 last[u] = val[f[u]]?f[u]:last[f[u]];
    151             }
    152         }
    153     }
    154     
    155 };
    156 
    157 AC ac;
    158 
    159 int main()
    160 {
    161     ios::sync_with_stdio(false);
    162     cin.tie(0);
    163     while (cin >> n && n)
    164     {
    165         ms.clear();
    166         Reset(cnt, 0);
    167         ac.init();
    168         repn(i, n)
    169         {
    170             cin >> input[i];
    171             ms[input[i]] = i;
    172         }
    173         cin >> text;
    174         for (auto &pr : ms)
    175         {
    176             ac.insert(pr.first, pr.second);
    177         }
    178         ac.get_fail();
    179         ac.find(text);
    180         int best = 0;
    181         for (int i = 1; i <= n; ++i) best = max(best, cnt[i]);
    182         cout << best << newline;
    183         for (int i = 1; i <= n; ++i)
    184             if (cnt[ms[input[i]]] == best)
    185                 cout << input[i] << newline;
    186     }
    187 }
    View Code
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  • 原文地址:https://www.cnblogs.com/skyette/p/6361654.html
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