题目描述:(链接)
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
解题思路:
排序,左右夹逼!
class Solution { public: int threeSumClosest(vector<int>& nums, int target) { int result = 0; if (nums.size() < 3) { return result; } int min = INT_MAX; sort(nums.begin(), nums.end()); auto last = nums.end(); for (auto i = nums.begin(); i != prev(last, 2); ++i) { auto j = i + 1; auto k = last - 1; while (j < k) { int sum = *i + *j + *k; int gap = abs(sum - target); if (gap < min) { result = sum; min = gap; } if (sum < target) { ++j ; } else { --k; } } } return result; } };