题目:https://pintia.cn/problem-sets/1268384564738605056/problems/1271415149946912768
题解:https://blog.csdn.net/wanmeiwushang/article/details/52585327
题解代码:
List Merge(List L1, List L2) { List L = (List)malloc(sizeof(struct Node)); L->Next = NULL; List r = L; List p = L1->Next; List q = L2->Next; while (p!=NULL && q!=NULL) { if (p->Data < q->Data) { r->Next = p; p = p->Next; r = r->Next; } else { r->Next = q; q = q->Next; r = r->Next; } } if (p != NULL) r->Next = p; if (q != NULL) r->Next = q; L1->Next = NULL; L2->Next = NULL; return L; }
完整代码:
#include <stdio.h> #include <stdlib.h> typedef int ElementType; typedef struct Node* PtrToNode; struct Node { ElementType Data; PtrToNode Next; }; typedef PtrToNode List; List Read(); /* 细节在此不表 */ void Print(List L); /* 细节在此不表;空链表将输出NULL */ List Merge(List L1, List L2); int main() { List L1, L2, L; L1 = Read(); L2 = Read(); L = Merge(L1, L2); Print(L); Print(L1); Print(L2); return 0; } /* 你的代码将被嵌在这里 */ List Merge(List L1, List L2) { List L = (List)malloc(sizeof(struct Node)); L->Next = NULL; List r = L; List p = L1->Next; List q = L2->Next; while (p!=NULL && q!=NULL) { if (p->Data < q->Data) { r->Next = p; p = p->Next; r = r->Next; } else { r->Next = q; q = q->Next; r = r->Next; } } if (p != NULL) r->Next = p; if (q != NULL) r->Next = q; L1->Next = NULL; L2->Next = NULL; return L; } List Read() { int len = 0; int num = 0; PtrToNode h = NULL; PtrToNode last = NULL; scanf("%d", &len); if (len == 0) return NULL; h = (PtrToNode)malloc(sizeof(struct Node));//建立头结点 h->Next = NULL; last = h; while (len) { scanf("%d", &num); PtrToNode node = (PtrToNode)malloc(sizeof(struct Node)); node->Data = num; node->Next = NULL; last->Next = node; last = node; len--; } return h; } void Print(List L) { if (L->Next == NULL) { printf("NULL "); return; } L = L->Next; while (L != NULL) { printf("%d ", L->Data); L = L->Next; } putchar(' '); }