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- 在C++中调用Python代码时的返回值问题
基础类型
修改Python脚本(build/zoo.py)
def rint():
return 2
def rstr():
return "fwd"
if __name__ == '__main__':
pass
修改源文件(main.cpp)
#include <iostream>
#include <boost/python.hpp>
using namespace boost::python;
using namespace boost::python::detail;
int main()
{
Py_Initialize();
if (!Py_IsInitialized())
{
std::cout << "Initialize failed" << std::endl;
return -1;
}
try
{
object sys_module = import("sys");
str module_directory(".");
sys_module.attr("path").attr("insert")(1, module_directory);
object module = import("zoo");
object x = module.attr("rint")();
int rx = extract<int>(x);
std::cout << "rint: " << rx << std::endl;
object y = module.attr("rstr")();
std::string rs = extract<std::string>(y);
std::cout << "rstr: " << rs << std::endl;
}
catch (const error_already_set&)
{
PyErr_Print();
}
Py_Finalize();
return 0;
}
标准库
修改Python脚本(build/zoo.py)
def rvec():
return [1, 2, 3, "fwd"]
if __name__ == '__main__':
pass
修改源文件(main.cpp)
#include <iostream>
#include <vector>
#include <string>
#include <boost/python.hpp>
using namespace boost::python;
using namespace boost::python::detail;
int main()
{
Py_Initialize();
if (!Py_IsInitialized())
{
std::cout << "Initialize failed" << std::endl;
return -1;
}
try
{
object sys_module = import("sys");
str module_directory(".");
sys_module.attr("path").attr("insert")(1, module_directory);
object module = import("zoo");
object v = module.attr("rvec")();
boost::python::handle<> v_iter(PyObject_GetIter(v.ptr()));
std::cout << "rvec: ";
while (true)
{
handle<> py_hdl(allow_null(PyIter_Next(v_iter.get())));
if (PyErr_Occurred())
throw_error_already_set();
if (!py_hdl.get())
break;
object py_obj(py_hdl);
object r = py_obj.attr("__str__")();
std::string rs = extract<std::string>(r);
std::cout << rs << " ";
}
std::cout << std::endl;
}
catch (const error_already_set&)
{
PyErr_Print();
}
Py_Finalize();
return 0;
}