天干地支纪年法

如何计算当前年份是天干地支哪一年？

# -*- coding: utf-8 -*-
'''
判断今年是什么年份,例如：2019年为己亥年
'''
TG=['甲','乙','丙','丁','戊','己','庚','辛','壬','癸']
DZ=['子','丑','寅','卯','辰','巳','午','未','申','酉','戌','亥']
Year_Name=[]
x=0
y=0
n=1
while n<61:
    if x==y and x<10:
        Year_Name.append(TG[x]+DZ[y])
        x+=1
        y+=1
    elif x<10 and y>=12:
        y=y*0
        Year_Name.append(TG[x]+DZ[y])
        x+=1
        y+=1
    elif 9<x<=10 and 12>y>=10:
        x = x * 0
        Year_Name.append(TG[x] + DZ[y])
        x+=1
        y+=1
    elif x<10 and y<10:
        Year_Name.append(TG[x] + DZ[y])
        x+=1
        y+=1
    elif x<10 and  12>y>=10:
        Year_Name.append(TG[x] + DZ[y])
        x += 1
        y += 1
    elif x == 10 and y<12:
        x=x*0
        Year_Name.append(TG[x] + DZ[y])
        x += 1
        y += 1
    else:
        pass
    n+=1
# print(Year_Name)
# 1984 甲子年
Year=1984
Year_Num=[]
Year_Num.clear()
while (Year<2085):
    Year_Num.append(Year)
    Year=Year+1
# print(Year_Num)

dic={}
dic.clear()
i=0
n=0
if i==0:
    for n in range(0,len(Year_Num),1):
        dic[Year_Num[n]] = Year_Name[i]
        i += 1
        if i == 60:
            i = i * 0
Year_S=input("请输入年份:")
print(dic.get(int(Year_S)))