数字转中文大写=> 1234=> 一千二百三十四

# -*- coding: utf-8 -*-
# 最大值:九兆九千九百九十九亿九千九百九十九万九千九百九十九
import re
p = ['', '十', '百', '千', '万', '十', '百', '千', '亿', '十', '百', '千', '兆']
s = ['', '一', '二', '三', '四', '五', '六', '七', '八', '九']
def num2zh(num_str):
    res = ''
    t = list(str(num_str))
    t.reverse()
    for idx, tmp in enumerate(t):
        if int(tmp) == 0:
            res = '零' + res
            if idx % 4 == 0 and idx > 0:
                res = p[idx] + res
            continue
        res = s[int(tmp)] + p[idx] + res
    # 零+ -> 零
    out = re.sub(r'(xe9x9bxb6)+', '零', res)
    # 零万 -> 万
    out = re.sub(r'xe9x9bxb6xe4xb8x87', '万', out)
    # 一十 -> 十
    out = re.sub(r'(^xe4xb8x80xe5x8dx81)', '十', out)
    # 零亿 -> 亿 
    out = re.sub(r'xe9x9bxb6xe4xbaxbf', '亿', out)
    # 亿万 -> 亿 
    out = re.sub(r'xe4xbaxbfxe4xb8x87', '亿', out)
    # 兆亿 -> 兆 
    out = re.sub(r'xe5x85x86xe4xbaxbf', '兆', out)
    # 去掉最后的零
    out = re.sub(r'(xe9x9bxb6)$', '', out)
    return out
print(num2zh(1234))