• 线索化二叉树


    package com.dai.tree.threadedbinarytree;
    
    public class ThreadedBinaryTreeDemo {
    
        public static void main(String[] args) {
            //测试中序线索二叉树功能是否正确
            HeroNode root = new HeroNode(1, "Tom");
            HeroNode node2 = new HeroNode(3, "jack");
            HeroNode node3 = new HeroNode(6, "huahua");
            HeroNode node4 = new HeroNode(8, "mary");
            HeroNode node5 = new HeroNode(10, "king");
            HeroNode node6 = new HeroNode(14, "dim");
            //手动创建
            root.setLeft(node2);
            root.setRight(node3);
            node2.setLeft(node4);
            node2.setRight(node5);
            node3.setLeft(node6);
            
            ThreadedBinaryTree threadedBinaryTree = new ThreadedBinaryTree();
            threadedBinaryTree.setRoot(root);
            threadedBinaryTree.threadedNodes();
            //测试10号节点
            HeroNode leftNode = node5.getLeft();
            HeroNode rightNode = node5.getRight();
            System.out.println("10号节点的前驱节点是:" + leftNode);
            System.out.println("10号节点的后继节点是:" + rightNode);
        }
    
    }
    
    //定义threadedBinaryTree 二叉树
    class ThreadedBinaryTree{
        private HeroNode root;
        //为实现线索化,需要创建要给指向当前节点的前驱节点的指针
        private HeroNode pre = null;
        //递归线索化时,pre总是保留前一个节点
        public void setRoot(HeroNode root) {
            this.root = root;
        } 
        //重载线索化二叉树的方法
        public void threadedNodes() {
            this.threadedNodes(root);
        }
        //编写对二叉树中序线索化的代码
        /**
         * 
         * @param node:当前需要线索化的节点
         */
        public void threadedNodes(HeroNode node) {
            if(node == null) {
                return ; //节点为空直接返回
            }
            //线索化左子树
            threadedNodes(node.getLeft());
            if(node.getLeft() == null) {
                node.setLeft(pre);
                node.setLeftType(1);
            }
            if(pre != null && pre.getRight() == null) {
                pre.setRight(node);
                pre.setRightType(1);
            }
            pre = node;
            
            //线索化右子树
            threadedNodes(node.getRight());
            
            
        }
        //删除节点
        public void delNode(int no) {
            if(root != null) {
            //如果只有一个root节点,这里需要判断root是不是要删除的节点。
                if(root.getNo() == no) {
                    root = null;
                }else {
                    //递归删除
                    root.delNode(no);
                }
                
            }else {
                System.out.println("树空,无法删除");
            }
        }
        //前序遍历
        public void preOrder() {
            if(this.root != null) {
                this.root.preOrder();
            }else {
                System.out.println("二叉树为空,无法遍历");
            }
        }
        
        //中序遍历
        public void infixOrder() {
            if(this.root != null) {
                this.root.infixOrder();
            }else {
                System.out.println("二叉树为空,无法遍历");
            }
        }
        
        //后序遍历
        public void postOrder() {
            if(this.root != null) {
                this.root.postOrder();
            }else {
                System.out.println("二叉树为空,无法遍历");
            }
        }
        //前序遍历查找
        public HeroNode preOrderSearch(int no) {
            if(root != null) {
                return root.preOrdersearch(no);
            }else {
                return null;
            }
        }
        
        //中序遍历查找
        public HeroNode infixOrderSearch(int no) {
            if(root != null) {
                return root.infixOrdersearch(no);
            }else {
                return null;
            }
        }
            //后序遍历查找
        public HeroNode postOrderSearch(int no) {
            if(root != null) {
                return root.postOrdersearch(no);
            }else {
                return null;
            }
        }
    }
    
    //节点类
    class HeroNode{
        private int no;
        private String name;
        private HeroNode left;
        private HeroNode right;
        //leftType为0表示左子树,1表示指向前驱节点
        //rightType为0表示右子树,1表示后继
        private int leftType;
        private int rightType;
    
        public HeroNode(int no, String name) {
            this.no = no;
            this.name = name;
        }
        
        public int getLeftType() {
            return leftType;
        }
    
        public void setLeftType(int leftType) {
            this.leftType = leftType;
        }
    
        public int getRightType() {
            return rightType;
        }
    
        public void setRightType(int rightType) {
            this.rightType = rightType;
        }
    
        public int getNo() {
            return no;
        }
        public void setNo(int no) {
            this.no = no;
        }
        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public HeroNode getLeft() {
            return left;
        }
        public void setLeft(HeroNode left) {
            this.left = left;
        }
        public HeroNode getRight() {
            return right;
        }
        public void setRight(HeroNode right) {
            this.right = right;
        }
        
        @Override
        public String toString() {
            return "HeroNode [no=" + no + ", name=" + name + "]";
        }
        
        //递归删除节点
        //叶子节点则删除,非叶子节点,则要删除子树
        public void delNode(int no) {
            if(this.left != null && this.left.no == no) {
                this.left = null;
                return;
            }
            if(this.right != null && this.right.no ==no) {
                this.right = null ;
                return ;
            }
            if(this.left != null) {
                this.left.delNode(no);
            }
            if(this.right != null) {
                this.right.delNode(no);
            }
        }
        
        //编写前序遍历的方法
        public void preOrder() {
            System.out.println(this); //
            //递归向左子数
            if(this.left != null) {
                this.left.preOrder();
            }
            //递归向右前序遍历
            if(this.right!=null) {
                this.right.preOrder();
            }
            
        }
        //中序遍历
        public void infixOrder() {
            //递归向左子树中序遍历
            if(this.left != null) {
                this.left.infixOrder();
            }
            System.out.println(this);
            if(this.right != null) {
                this.right.infixOrder();
            }
        }
        
        //后续遍历
        public void postOrder() {
            if(this.left != null) {
                this.left.postOrder();
            }
            if(this.right != null) {
                this.right.postOrder();
            }
            System.out.println(this);
        }
        //前序遍历查找
        public HeroNode preOrdersearch(int no) {
            //比较当前节点是不是
            if(this.no==no) {
                return this;
            }
            HeroNode resNode =null;
            if(this.left != null) {
                resNode = this.left.preOrdersearch(no);
            }
            if(resNode != null) {
                return resNode;
            }
            if(this.right != null) {
                resNode = this.right.preOrdersearch(no);
            }
            return resNode;
        }
        //中序遍历查找
        public HeroNode infixOrdersearch(int no) {
            
            HeroNode resNode =null;
            if(this.left != null) {
                resNode = this.left.infixOrdersearch(no);
            }
            if(resNode != null) {
                return resNode;
            }
            if(this.no==no) {
                return this;
            }
            if(this.right != null) {
                resNode = this.right.infixOrdersearch(no);
            }
            return resNode;
        }
            //后序遍历查找
            public HeroNode postOrdersearch(int no) {
                HeroNode resNode =null;
                if(this.left != null) {
                    resNode = this.left.postOrdersearch(no);
                }
                if(resNode != null) {
                    return resNode;
                }
                if(this.right != null) {
                    resNode = this.right.postOrdersearch(no);
                }
                if(resNode != null) {
                    return resNode;
                }
                
                if(this.no==no) {
                    return this;
                }
                return resNode;
            }
    }
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  • 原文地址:https://www.cnblogs.com/shengtudai/p/14454511.html
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