简单题 线段树的单点更新 就是字符串神马的 有点小繁琐 开两个map 一个存城市 一个存名字
1 #include <iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 #include<cstdlib> 6 #include<string> 7 #include<map> 8 using namespace std; 9 #define N 60010 10 #define LL long long 11 LL s[N<<2]; 12 LL a[N],pp[N]; 13 map<string,int>q; 14 map<string,int>qq; 15 char pq[N][25]; 16 struct node 17 { 18 int d; 19 char s1[25]; 20 char s2[25]; 21 }bi[N]; 22 struct mode 23 { 24 char ss[25]; 25 LL vv; 26 }ct[N]; 27 int sd[N],g,gg,lo[N]; 28 void up(int w) 29 { 30 s[w] = max(s[w<<1],s[w<<1|1]); 31 } 32 void build(int l,int r,int w) 33 { 34 if(l==r) 35 { 36 s[w] = a[l]; 37 return ; 38 } 39 int m = (l+r)>>1; 40 build(l,m,w<<1); 41 build(m+1,r,w<<1|1); 42 up(w); 43 } 44 void update(int p,LL d,int l,int r,int w) 45 { 46 if(l==r) 47 { 48 s[w]+=d; 49 return ; 50 } 51 int m = (l+r)>>1; 52 if(p<=m) 53 update(p,d,l,m,w<<1); 54 else 55 update(p,d,m+1,r,w<<1|1); 56 up(w); 57 } 58 int query(int l,int r,int w) 59 { 60 if(l==r) 61 { 62 return l; 63 } 64 int m = (l+r)>>1; 65 if(s[w<<1]>s[w<<1|1]) 66 return query(l,m,w<<1); 67 else if(s[w<<1]<s[w<<1|1]) 68 return query(m+1,r,w<<1|1); 69 else 70 return 0; 71 } 72 bool cmp(mode a,mode b) 73 { 74 return strcmp(a.ss,b.ss)<0; 75 } 76 int main() 77 { 78 int n,k,m,i; 79 char s1[25],s2[25]; 80 LL p; 81 scanf("%d",&n); 82 for(i = 1; i <= n ; i++) 83 { 84 scanf("%s%s %lld",s1,s2,&p); 85 if(!q[s2]) 86 { 87 g++; 88 q[s2] = g; 89 a[q[s2]]+=p; 90 strcpy(pq[g],s2); 91 } 92 else 93 a[q[s2]]+=p; 94 if(!qq[s1]) 95 { 96 gg++; 97 qq[s1] = gg; 98 pp[gg] = p; 99 } 100 lo[qq[s1]] = q[s2]; 101 } 102 scanf("%d%d",&m,&k); 103 for(i = 1; i <= k ; i++) 104 { 105 scanf("%d%s%s",&bi[i].d,bi[i].s1,bi[i].s2); 106 if(!q[bi[i].s2]) 107 { 108 g++; 109 q[bi[i].s2] = g; 110 strcpy(pq[g],bi[i].s2); 111 } 112 } 113 build(1,g,1); 114 int o = query(1,g,1); 115 int t = 0; 116 for(i = 1 ; i <= k ; i++) 117 { 118 int o1 = qq[bi[i].s1]; 119 int o2 = q[bi[i].s2]; 120 int kk = bi[i].d; 121 if(o) 122 { 123 sd[o]+=(kk-t); 124 } 125 t = kk; 126 update(lo[o1],-pp[o1],1,g,1); 127 update(o2,pp[o1],1,g,1); 128 lo[o1] = o2; 129 o = query(1,g,1); 130 } 131 if(o) 132 sd[o] += m-t; 133 o = 0; 134 for(i = 1; i <= g ; i++) 135 { 136 if(sd[i]) 137 { 138 strcpy(ct[o].ss,pq[i]); 139 ct[o].vv = sd[i]; 140 o++; 141 } 142 } 143 sort(ct,ct+o,cmp); 144 for(i = 0 ; i < o ; i++) 145 printf("%s %lld ",ct[i].ss,ct[i].vv); 146 return 0; 147 }