• leetcode-1-两数之和(三种方法)


    #include<vector>
    #include<map>
    #include<iostream>
    using namespace std;
    
    /*暴力遍历
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> ret;
        if(nums.size()<2)
            return ret;
        for(int i = 0;i<nums.size()-1;i++)
        {
            for(int j = i+1;j<nums.size();j++)
            {
                if(nums[i]+nums[j]==target)
                {
                    ret.push_back(i);
                    ret.push_back(j);
                }
            }
        }
        return ret;
    }
        */
        /*两遍哈希表
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> vi;
        map<int,int> hashmap;
        pair<map<int,int>::iterator,bool> insertpair;//判断插入成功与否
        for(int i = 0;i<nums.size();i++){
            //hashmap.insert(pair<int,int>(nums[i],i));
            insertpair = hashmap.insert(map<int,int>::value_type(nums[i],i));
            if(insertpair.second==false)
            {//插入失败,判断当前数是否为target的一半
                if(nums[i]*2==target){
                    vi.push_back(insertpair.first->second);
                    vi.push_back(i);
                    return vi;
                }
            }
        }
        int den;
        for(int i = 0;i<nums.size();i++){
            den = target - nums[i];
            auto iter = hashmap.find(den);
            if(iter!=hashmap.end()&&iter->second!=i)
            {
                vi.push_back(i);
                vi.push_back(iter->second);
                return vi;
            }
        }
        return vi;
    }
        */
        //一次遍历哈希
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> vi;
        map<int, int> hashmap;
        pair<map<int, int>::iterator, bool> insertpair;//判断插入成功与否
        for (int i = 0; i < nums.size(); i++) {
            //hashmap.insert(pair<int,int>(nums[i],i));
            insertpair = hashmap.insert(map<int, int>::value_type(nums[i], i));
            if (insertpair.second == false)
            {//插入失败,判断当前数是否为target的一半
                if (nums[i] * 2 == target) {
                    vi.push_back(insertpair.first->second);
                    vi.push_back(i);
                    return vi;
                }
            }
            else {//如果插入成功,判断另一个数是否在hash表中
                auto iter = hashmap.find(target - nums[i]);
                if (iter != hashmap.end()) {
                    if (iter->second != i)
                    {
                        vi.push_back(iter->second);
                        vi.push_back(i);
                        return vi;
                    }
    
                }
            }
        }
        return vi;
    }
    
    int main()
    {
        vector<int> vi1({3,3});
        vector<int> vi2({1,7,4,8,13});
        vector<int> ret;
        ret = twoSum(vi1, 6);
        for (auto i : ret)
            cout << i << "	";
        cout << endl;
        ret = twoSum(vi2, 15);
        for (auto i : ret)
            cout << i << "	";
        cout << endl;
    }
    
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  • 原文地址:https://www.cnblogs.com/sgawscd/p/13678555.html
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