题目如下:
Given a
date
string in the formDay Month Year
, where:
Day
is in the set{"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}
.Month
is in the set{"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}
.Year
is in the range[1900, 2100]
.Convert the date string to the format
YYYY-MM-DD
, where:
YYYY
denotes the 4 digit year.MM
denotes the 2 digit month.DD
denotes the 2 digit day.Example 1:
Input: date = "20th Oct 2052" Output: "2052-10-20"Example 2:
Input: date = "6th Jun 1933" Output: "1933-06-06"Example 3:
Input: date = "26th May 1960" Output: "1960-05-26"Constraints:
- The given dates are guaranteed to be valid, so no error handling is necessary.
解题思路:day去掉后缀,剩下的数字前面补0直到补齐为两位,month直接转换,year不变。
代码如下:
class Solution(object): def reformatDate(self, date): """ :type date: str :rtype: str """ monthes = ["","Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"] item = date.split(" ") day = item[0].replace('th','').replace('st','').replace('nd','').replace('rd','').zfill(2) month = str(monthes.index(item[1])).zfill(2) return item[2]+'-' + month + '-' + day