题目如下:
Given an array
nums
. We define a running sum of an array asrunningSum[i] = sum(nums[0]…nums[i])
.Return the running sum of
nums
.Example 1:
Input: nums = [1,2,3,4] Output: [1,3,6,10] Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].Example 2:
Input: nums = [1,1,1,1,1] Output: [1,2,3,4,5] Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].Example 3:
Input: nums = [3,1,2,10,1] Output: [3,4,6,16,17]
解题思路:送分题。
代码如下:
class Solution(object): def runningSum(self, nums): """ :type nums: List[int] :rtype: List[int] """ res = [] count = 0 for i in nums: count += i res.append(count) return res