题目如下:
Given an integer
n
, return any array containingn
unique integers such that they add up to 0.Example 1:
Input: n = 5 Output: [-7,-1,1,3,4] Explanation: These arrays also are accepted [-5,-1,1,2,3] , [-3,-1,2,-2,4].Example 2:
Input: n = 3 Output: [-1,0,1]Example 3:
Input: n = 1 Output: [0]Constraints:
1 <= n <= 1000
解题思路:很简单,如果n是偶数,例如6,那么就是[-3,-2,-1,1,2,3],如果是奇数,比如7,那么在[-3,-2,-1,1,2,3]的基础上加一个0即可。
代码如下:
class Solution(object): def sumZero(self, n): """ :type n: int :rtype: List[int] """ res = [] if n % 2 == 1: res.append(0) count = n/2 while count > 0: res.append(count) res.append(-count) count -= 1 return res