• mysql on、having、where、order by、group by的用法笔记


    创建mysql的测试表

    SET FOREIGN_KEY_CHECKS=0; -- 影响的是当前页面,没改变全局的设置
    
    -- ----------------------------
    -- Table structure for dept
    -- ----------------------------
    DROP TABLE IF EXISTS `dept`;
    CREATE TABLE `dept` (
      `deptno` int(2) NOT NULL COMMENT '部门编号',
      `dname` varchar(14) DEFAULT NULL COMMENT '部门名称',
      `loc` varchar(13) DEFAULT NULL COMMENT '部门地址',
      PRIMARY KEY (`deptno`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COMMENT='部门表';
    
    -- ----------------------------
    -- Records of dept
    -- ----------------------------
    INSERT INTO `dept` VALUES ('10', 'ACCOUNTING', 'NEW YORK');
    INSERT INTO `dept` VALUES ('20', 'RESEARCH', 'DALLAS');
    INSERT INTO `dept` VALUES ('30', 'SALES', 'CHICAGO');
    INSERT INTO `dept` VALUES ('40', 'OPERATIONS', 'BOSTON');
    
    -- ----------------------------
    -- Table structure for emp
    -- ----------------------------
    DROP TABLE IF EXISTS `emp`;
    CREATE TABLE `emp` (
      `empno` int(4) NOT NULL COMMENT '员工号',
      `ename` varchar(10) DEFAULT NULL COMMENT '员工姓名',
      `job` varchar(9) DEFAULT NULL COMMENT '工作岗位',
      `mgr` int(4) DEFAULT NULL COMMENT '领导编号',
      `hiredate` date DEFAULT NULL COMMENT '入职时间',
      `sal` int(7) DEFAULT NULL COMMENT 'salary工资',
      `comm` int(7) DEFAULT NULL COMMENT 'commission 佣金',
      `deptno` int(2) DEFAULT NULL COMMENT '部门编号',
      PRIMARY KEY (`empno`),
      KEY `fk_deptno` (`deptno`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COMMENT='员工表';
    
    -- ----------------------------
    -- Records of emp
    -- ----------------------------
    INSERT INTO `emp` VALUES ('7369', 'SMITH', 'CLERK', '7902', '1980-12-17', '800', null, '20');
    INSERT INTO `emp` VALUES ('7499', 'ALLEN', 'SALESMAN', '7698', '1981-02-20', '1600', '300', '30');
    INSERT INTO `emp` VALUES ('7521', 'WARD', 'SALESMAN', '7698', '1981-02-22', '1250', '500', '30');
    INSERT INTO `emp` VALUES ('7566', 'JONES', 'MANAGER', '7839', '1981-04-02', '2975', null, '20');
    INSERT INTO `emp` VALUES ('7654', 'MARTIN', 'SALESMAN', '7698', '1981-09-28', '1250', '1400', '30');
    INSERT INTO `emp` VALUES ('7698', 'BLAKE', 'MANAGER', '7839', '1981-05-01', '2850', null, '30');
    INSERT INTO `emp` VALUES ('7782', 'CLARK', 'MANAGER', '7839', '1981-06-09', '2450', null, '10');
    INSERT INTO `emp` VALUES ('7788', 'SCOTT', 'ANALYST', '7566', '1987-04-19', '3000', null, '20');
    INSERT INTO `emp` VALUES ('7839', 'KING', 'PRESIDENT', null, '1981-11-17', '5000', null, '10');
    INSERT INTO `emp` VALUES ('7844', 'TURNER', 'SALESMAN', '7698', '1981-09-08', '1500', '0', '30');
    INSERT INTO `emp` VALUES ('7876', 'ADAMS', 'CLERK', '7788', '1987-05-23', '1100', null, '20');
    INSERT INTO `emp` VALUES ('7900', 'JAMES', 'CLERK', '7698', '1981-12-03', '950', null, '30');
    INSERT INTO `emp` VALUES ('7902', 'FORD', 'ANALYST', '7566', '1981-12-03', '3000', null, '20');
    INSERT INTO `emp` VALUES ('7934', 'MILLER', 'CLERK', '7782', '1982-01-23', '1300', null, '10');
    INSERT INTO `emp` VALUES ('8000', 'SEASON', 'CLERK', '7782', '1999-01-23', '1300', null, '50');
    
    -- ----------------------------
    -- Table structure for salgrade
    -- ----------------------------
    DROP TABLE IF EXISTS `salgrade`;
    CREATE TABLE `salgrade` (
      `grade` decimal(10,0) NOT NULL COMMENT '工资级别',
      `losal` decimal(10,0) DEFAULT NULL COMMENT '最低工资',
      `hisal` decimal(10,0) DEFAULT NULL COMMENT '最高工资',
      PRIMARY KEY (`grade`)
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COMMENT='工资级别';
    
    -- ----------------------------
    -- Records of salgrade
    -- ----------------------------
    INSERT INTO `salgrade` VALUES ('1', '700', '1200');
    INSERT INTO `salgrade` VALUES ('2', '1201', '1400');
    INSERT INTO `salgrade` VALUES ('3', '1401', '2000');
    INSERT INTO `salgrade` VALUES ('4', '2001', '3000');
    INSERT INTO `salgrade` VALUES ('5', '3001', '9999');
    
    1. 关于他们之间的区别,之前查过,但是总是会弄糊涂,搞不清,所以我专门记下来,下次遇到疑问的时候,直接在这里查找就行。
      话不多说,开始进入正题吧
      首先得有测试数据,所以呢,我找到了oracle的3张测试表以及相关的测试数据,而这就基本够我们使用了

    2. 执行的顺序:on -> where -> group by -> having -> order by
      where在group by 之前,是为了先过滤单表/视图/结果集,再JOIN

    3. 特殊的用法:

    1. 在inner join 中,可以将where的条件全部迁移到on的后面,也就是说on与where都可以对表进行限制
    2. having后面可以对聚合后的数据进行条件过滤,对于非聚合的数据,比如查询中加减,也应该在having中处理(非聚合sql也可以)
    3. where只能对原始的数据进行条件过滤,加工后的数据需要用having处理,同上一条一致
    
    1. 另外需要注意的:在left join 语句中,on后面的条件不会影响到左表,right join同理,而这时就需要考虑on与where的选择了
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  • 原文地址:https://www.cnblogs.com/season-qd/p/13489336.html
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