• Codility---MaxDoubleSliceSum


    Task description

    A non-empty zero-indexed array A consisting of N integers is given.

    A triplet (X, Y, Z), such that 0 ≤ X < Y < Z < N, is called a double slice.

    The sum of double slice (X, Y, Z) is the total of A[X + 1] + A[X + 2] + ... + A[Y − 1] + A[Y + 1] + A[Y + 2] + ... + A[Z − 1].

    For example, array A such that:

    A[0] = 3 A[1] = 2 A[2] = 6 A[3] = -1 A[4] = 4 A[5] = 5 A[6] = -1 A[7] = 2

    contains the following example double slices:

    • double slice (0, 3, 6), sum is 2 + 6 + 4 + 5 = 17,
    • double slice (0, 3, 7), sum is 2 + 6 + 4 + 5 − 1 = 16,
    • double slice (3, 4, 5), sum is 0.

    The goal is to find the maximal sum of any double slice.

    Write a function:

    class Solution { public int solution(int[] A); }

    that, given a non-empty zero-indexed array A consisting of N integers, returns the maximal sum of any double slice.

    For example, given:

    A[0] = 3 A[1] = 2 A[2] = 6 A[3] = -1 A[4] = 4 A[5] = 5 A[6] = -1 A[7] = 2

    the function should return 17, because no double slice of array A has a sum of greater than 17.

    Assume that:

    • N is an integer within the range [3..100,000];
    • each element of array A is an integer within the range [−10,000..10,000].

    Complexity:

    • expected worst-case time complexity is O(N);
    • expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).

    Elements of input arrays can be modified.

    Solution
     
    Programming language used: Java
     
    Code: 00:31:25 UTC, java, final, score:  100
    // you can also use imports, for example:
    // import java.util.*;
    
    // you can write to stdout for debugging purposes, e.g.
    // System.out.println("this is a debug message");
    import java.lang.Math;
    class Solution {
        public int solution(int[] A) {
            // write your code in Java SE 8
            if(A.length < 4)
                return 0;
            int maxleft=0, maxending=0, maxslice=0;
            for(int i=3; i<A.length; i++) {
                maxleft = Math.max(maxleft+A[i-2], A[i-2]);
                maxending = Math.max(maxleft, Math.max( A[i-1], maxending+A[i-1]));
                maxslice = Math.max(maxending, maxslice);
            }
            return maxslice;
        }
    }


    https://codility.com/demo/results/trainingEJXAE5-H5P/
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  • 原文地址:https://www.cnblogs.com/samo/p/6991108.html
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