• [Bzoj1195][HNOI2006]最短母串(AC自动机)


    题目链接:https://www.lydsy.com/JudgeOnline/problem.php?id=1195

    多个字符串匹配问题用AC自动机没跑了,建好AC自动机后,由于要求答案要最短和字典序最小,则在AC自动机上状压bfs搜索,bfs保证搜到的串长度最短,然后每次从A-Z遍历,保证搜到的字典序最小。状态压缩成在AC自动机上节点i时,包含了串的状态为j,最后状态为(1<<n)-1时停止。

    偷偷懒用cin...

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 typedef long long ll;
     4 int n;
     5 bool vis[610][4100];
     6 struct node {
     7     int num, st;
     8     string ans;
     9 };
    10 struct ACzd {
    11     int AC[610][26];
    12     int fail[610];
    13     int numend[610];
    14     int len, root;
    15     int newcode() {
    16         memset(AC[len], 0, sizeof(AC[len]));
    17         numend[len] = 0;
    18         return len++;
    19     }
    20     void init() {
    21         len = 0;
    22         root = newcode();
    23     }
    24     void build(char *s, int id) {
    25         int k = strlen(s);
    26         int now = root;
    27         for (int i = 0; i < k; i++) {
    28             if (AC[now][s[i] - 'A'] == 0)
    29                 AC[now][s[i] - 'A'] = newcode();
    30             now = AC[now][s[i] - 'A'];
    31         }
    32         numend[now] |= (1 << id);
    33     }
    34     void get_fail() {
    35         fail[root] = root;
    36         queue<int>q;
    37         for (int i = 0; i < 26; i++) {
    38             if (AC[root][i] != 0) {
    39                 fail[AC[root][i]] = root;
    40                 q.push(AC[root][i]);
    41             }
    42             else
    43                 AC[root][i] = root;
    44         }
    45         while (!q.empty()) {
    46             int now = q.front();
    47             q.pop();
    48             numend[now] |= numend[fail[now]];
    49             for (int i = 0; i < 26; i++) {
    50                 if (AC[now][i] != 0) {
    51                     fail[AC[now][i]] = AC[fail[now]][i];
    52                     q.push(AC[now][i]);
    53                 }
    54                 else
    55                     AC[now][i] = AC[fail[now]][i];
    56             }
    57         }
    58     }
    59     string solve() {
    60         queue<node>q;
    61         int endst = (1 << n) - 1;
    62         q.push({ root,0,"" });
    63         while (!q.empty()) {
    64             node p = q.front();
    65             q.pop();
    66             if (p.st == endst) {
    67                 return p.ans;
    68             }
    69             for (int i = 0; i < 26; i++) {
    70                 int Nextnum = AC[p.num][i];
    71                 int Nextst = p.st | numend[Nextnum];
    72                 if (!vis[Nextnum][Nextst]) {
    73                     vis[Nextnum][Nextst] = 1;
    74                     q.push({ Nextnum,Nextst,p.ans + (char)(i + 'A') });
    75                 }
    76             }
    77         }
    78     }
    79 }AC;
    80 char s[55];
    81 int main() {
    82     ios::sync_with_stdio(0);
    83     while (cin >> n) {
    84         AC.init();
    85         for (int i = 0; i < n; i++) {
    86             cin >> s;
    87             AC.build(s, i);
    88         }
    89         AC.get_fail();
    90         string ans = AC.solve();
    91         cout << ans << endl;
    92     }
    93 }
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  • 原文地址:https://www.cnblogs.com/sainsist/p/11130277.html
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