• HYSBZ 2243 染色 树链剖分 线段树


    这题对最简单的树链剖分做了一些变化,在链的转移过程中要考虑前后链相邻节点颜色是否相同。

    对于线段树,只要维护三个值,左端点颜色,右端点颜色还有区间颜色总数就好了。

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <map>
    #include <set>
    #include <bitset>
    #include <queue>
    #include <stack>
    #include <string>
    #include <iostream>
    #include <cmath>
    #include <climits>
    
    using namespace std;
    
    #define lson rt << 1, l, mid
    #define rson rt << 1 | 1, mid + 1, r
    
    const int maxn = 1e5 + 10;
    int head[maxn], nxt[maxn << 1], u[maxn << 1], v[maxn << 1];
    int tid[maxn], maxson[maxn], siz[maxn], top[maxn], idcnt, ecnt;
    int lcnt[maxn << 2], lbdc[maxn << 2], rbdc[maxn << 2], lazy[maxn << 2];
    int n, m, scol[maxn], sval[maxn], dep[maxn], fa[maxn];
    
    void init() {
    	memset(head, -1, sizeof(head));
    	memset(maxson, -1, sizeof(maxson));
    	idcnt = ecnt = 0;
    }
    
    void adde(int uu, int vv) {
    	u[ecnt] = uu; v[ecnt] = vv;
    	nxt[ecnt] = head[uu]; head[uu] = ecnt++;
    }
    
    void dfs1(int now, int nowfa, int nowdep) {
    	dep[now] = nowdep; fa[now] = nowfa; siz[now] = 1;
    	for(int i = head[now]; ~i; i = nxt[i]) if(v[i] != nowfa) {
    		dfs1(v[i], now, nowdep + 1);
    		siz[now] += siz[v[i]];
    		if(maxson[now] == -1 || siz[maxson[now]] < siz[v[i]]) {
    			maxson[now] = v[i];
    		}
    	}
    }
    
    void dfs2(int now, int tp) {
    	top[now] = tp;
    	tid[now] = ++idcnt;
    	if(maxson[now] == -1) return;
    	dfs2(maxson[now], tp);
    	for(int i = head[now]; ~i; i = nxt[i]) {
    		if(v[i] != fa[now] && v[i] != maxson[now]) {
    			dfs2(v[i], v[i]);
    		}
    	}
    }
    
    void pushup(int rt) {
    	int lc = rt << 1, rc = rt << 1 | 1;
    	lcnt[rt] = lcnt[lc] + lcnt[rc];
    	lbdc[rt] = lbdc[lc]; rbdc[rt] = rbdc[rc];
    	if(rbdc[lc] == lbdc[rc]) lcnt[rt]--;
    }
    
    void fill(int rt, int Col) {
    	lazy[rt] = Col;
    	lcnt[rt] = 1;
    	lbdc[rt] = rbdc[rt] = Col;
    }
    
    void pushdown(int rt) {
    	if(lazy[rt] == -1) return;
    	int lc = rt << 1, rc = rt << 1 | 1;
    	fill(lc, lazy[rt]); fill(rc, lazy[rt]);
    	lazy[rt] = -1;
    }
    
    void build(int rt, int l, int r) {
    	lazy[rt] = -1;
    	if(l == r) {
    		lcnt[rt] = 1;
    		lbdc[rt] = rbdc[rt] = sval[l];
    	}
    	else {
    		int mid = (l + r) >> 1;
    		build(lson); build(rson);
    		pushup(rt);
    	}
    }
    
    void update(int rt, int l, int r, int ql, int qr, int Col) {
    	if(ql <= l && qr >= r) fill(rt, Col);
    	else {
    		int mid = (l + r) >> 1;
    		pushdown(rt);
    		if(ql <= mid) update(lson, ql, qr, Col);
    		if(qr > mid) update(rson, ql, qr, Col);
    		pushup(rt);
    	}
    }
    
    int query(int rt, int l, int r, int ql, int qr) {
    	if(ql <= l && qr >= r) return lcnt[rt];
    	else {
    		pushdown(rt);
    		int mid = (l + r) >> 1, ret = 0, lc = rt << 1, rc = rt << 1 | 1;
    		if(ql <= mid) ret += query(lson, ql, qr);
    		if(qr > mid) ret += query(rson, ql, qr);
    		if(ql <= mid && qr > mid && lbdc[rc] == rbdc[lc]) {
    			ret--;
    		}
    		pushup(rt);
    		return ret;
    	}
    }
    
    int query_Col(int rt, int l, int r ,int pos) {
    	if(l == r) return lbdc[rt];
    	pushdown(rt);
    	int mid = (l + r) >> 1, ret;
    	if(pos <= mid) ret = query_Col(lson, pos);
    	else ret = query_Col(rson, pos);
    	pushup(rt);
    	return ret;
    }
    
    int ask(int x, int y) {
    	int ret = 0;
    	while(top[x] != top[y]) {
    		if(dep[top[x]] < dep[top[y]]) swap(x, y);
    		ret += query(1, 1, idcnt, tid[top[x]], tid[x]);
    		int ca = query_Col(1, 1, idcnt, tid[top[x]]), 
    			cb = query_Col(1, 1, idcnt, tid[fa[top[x]]]);
    		if(ca == cb) ret--;
    		x = fa[top[x]];
    	}
    	if(dep[x] > dep[y]) swap(x, y);
    	ret += query(1, 1, idcnt, tid[x], tid[y]);
    	return ret;
    }
    
    void change(int x, int y, int Col) {
    	while(top[x] != top[y]) {
    		if(dep[top[x]] < dep[top[y]]) swap(x, y);
    		update(1, 1, idcnt, tid[top[x]], tid[x], Col);
    		x = fa[top[x]];
    	}
    	if(dep[x] > dep[y]) swap(x, y);
    	update(1, 1, idcnt, tid[x], tid[y], Col);
    }
    
    
    int main() {
    	while(scanf("%d%d", &n, &m) != EOF) {
    		init();
    		for(int i = 1; i <= n; i++) scanf("%d", &scol[i]);
    		for(int i = 1; i < n; i++) {
    			int a, b; scanf("%d%d", &a, &b);
    			adde(a, b); adde(b, a);
    		}
    		dfs1(1, 1, 1); dfs2(1, 1);
    		for(int i = 1; i <= n; i++) sval[tid[i]] = scol[i];
    		build(1, 1, idcnt);
    		char cmd[10]; int a, b, c;
    		for(int i = 1; i <= m; i++) {
    			scanf("%s", cmd);
    			if(cmd[0] == 'C') {
    				scanf("%d%d%d", &a, &b, &c);
    				change(a, b, c);
    			}
    			else {
    				scanf("%d%d", &a, &b);
    				printf("%d
    ", ask(a, b));
    			}
    		}
    	}
    	return 0;
    
    }
    

      

  • 相关阅读:
    结对作业
    黄金分割点(第五周 c语言版)
    小程序(第四周)
    读程序作业(第三周)
    vs2013的安装及测试(第三周)
    学习进度条(第6周)
    努力爬的蜗牛
    学习日记1
    团队作业(七)
    团队作业(六)
  • 原文地址:https://www.cnblogs.com/rolight/p/4075490.html
Copyright © 2020-2023  润新知