• poj 1459 (最大流)


    最大流简单题,,这题重要的是知道了scanf("%s",str);sscanf(str,"(%d,%d)%d",&x,&y,&w);读入方式






    #include<stdio.h>
    #include<string.h>
    const int N=210;
    const int inf=0x3fffffff;
    int dis[N],gap[N],head[N],num,start,end,ans,n,m;
    struct edge
    {
    	int st,ed,flow,next;
    }E[21000];
    struct node
    {
    	int x,y,w;
    }P[40000];
    void addedge(int x,int y,int w)
    {
    	E[num].st=x;E[num].ed=y;E[num].flow=w;E[num].next=head[x];head[x]=num++;
    	E[num].st=y;E[num].ed=x;E[num].flow=0;E[num].next=head[y];head[y]=num++;
    }
    int dfs(int u,int minflow)
    {
    	if(u==end)return minflow;
    	int i,v,f,flow=0,min_dis=ans-1;
    	for(i=head[u];i!=-1;i=E[i].next)
    	{
    		if(E[i].flow)
    		{
    			v=E[i].ed;
    			if(dis[v]+1==dis[u])
    			{
    				f=dfs(v,E[i].flow>minflow-flow?minflow-flow:E[i].flow);
    				E[i].flow-=f;
    				E[i^1].flow+=f;
    				flow+=f;
    				if(flow==minflow)break;
    				if(dis[start]>=ans)return flow;
    			}
    			min_dis=min_dis>dis[v]?dis[v]:min_dis;
    		}
    	}
    	if(flow==0)
    	{
    		if(--gap[dis[u]]==0)
    			dis[start]=ans;
    		dis[u]=min_dis+1;
    		gap[dis[u]]++;
    	}
    	return flow;
    }
    int isap()
    {
    	int maxflow=0;
    	memset(dis,0,sizeof(dis));
    	memset(gap,0,sizeof(gap));
    	gap[0]=ans;
    	while(dis[start]<ans)
    	   maxflow+=dfs(start,inf);
    	return maxflow;
    }
    int main()
    {
    	int i,k,x,y,w,t;
    	char str[20];
    	while(scanf("%d%d%d%d",&n,&m,&k,&t)!=-1)
    	{
    		start=0;end=n+1;ans=end+1;
    		memset(head,-1,sizeof(head));
    		num=0;
    		for(i=0;i<t;i++)
    		{
    			scanf("%s",str);
    			sscanf(str,"(%d,%d)%d",&x,&y,&w);
    			addedge(x+1,y+1,w);
    		}
    		for(i=0;i<m;i++)
    		{
    			scanf("%s",str);
    			sscanf(str,"(%d)%d",&x,&w);
    			addedge(start,x+1,w);
    		}
    		for(i=0;i<k;i++)
    		{
    			scanf("%s",str);
    			sscanf(str,"(%d)%d",&x,&w);
    			addedge(x+1,end,w);
    		}
    		printf("%d
    ",isap());
    
    	}
    	return 0;
    }
    
    


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  • 原文地址:https://www.cnblogs.com/riskyer/p/3253697.html
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