//说明: //高效求幂运算(递归) //输入:整数X,幂次N //输出:X^N //时间复杂度:O(logN) #include<iostream> using namespace std; int Pow(int X,int N) { if(N==0) return 1; else if(N==1) return X; else if(N%2==0) return Pow(X*X,N/2); else return Pow(X*X,N/2)*X; } void main() { cout<<"Input X and N:"<<endl; int X,N; cin>>X>>N; cout<<Pow(X,N)<<endl; }