一个用户下广告位 某一天有收入和支出 有支出不一定有收入 有收入不一定有支出 下例为按用户查询 sanhao 下的信息
支出如下：
收入如下：
按天进行查询，例如查询：
得到结果如下：
使用一般的按日期左关联，会出现错误。
正确的使用如下，把每个表的收入或者支出补全 为0，然后union合并 再进行分组合并
select rownum rn,mm0.accesstime,nvl(mm1.inall,0) inall
,nvl(mm1.outall,0) outall,mm1.placeid
,decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) profit
,decode(inall,0,'-', to_char(round((decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) )/inall,4)*100)||'%') proRate
from
(
select column_value as accesstime from table(fn_split('2013-10-12,2013-10-13,2013-10-14',',') )
) mm0,
(
select accesstime,placeid,sum(inall) inall,sum(outall2) outall from
(
--包广告位付款
select 0 inall,to_char(rd.accounttime,'yyyy-mm-dd') as accesstime,rd.placeid ,decode(sum(rd.paysum),null,0,sum(rd.paysum)) outall2
from ad_paidrecord rd
inner join ad_place pl on rd.placeid=pl.placeid and pl.ismonthly=1
where rd.placeid!=0--包广告位
and pl.ismonthly=1
and rd.rectype in(0,2)
and rd.accounttime>= to_date('2013-10-12','yyyy-mm-dd')
and rd.accounttime<= to_date('2013-10-14','yyyy-mm-dd')--根据记账日期（小的日期）
--and (i_placeid=-1 or rd.placeid=i_placeid)
and (rd.webuserid='sanhao' )
group by rd.accounttime,rd.placeid
union
--总收入
select sum(v.income)inall,to_char(v.accesstime,'yyyy-mm-dd') as accesstime,v.placeid,0
from v_placeincome v
where v.accesstime >= to_date('2013-10-12','yyyy-mm-dd')
and v.accesstime <= to_date('2013-10-14','yyyy-mm-dd')
-- and (i_placeid=-1 or v.placeid=i_placeid)
and v.ismonthly=1
and (v.webuserid='sanhao')
group by accesstime,placeid
)
group by accesstime,placeid
) mm1
where mm0.accesstime=mm1.accesstime(+)
and (inall>0 or (nvl(mm1.outall,0))>0)
order by placeid,mm0.accesstime asc;