Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
1 public class Solution { 2 public int threeSumClosest(int[] num, int target) { 3 if(num == null || num.length < 3) return 0; 4 int min = Integer.MAX_VALUE, len = num.length; 5 Arrays.sort(num); 6 for(int i = 0; i < len - 2; i ++){ 7 int goal = target - num[i]; 8 int j = i + 1, k = len - 1; 9 while(j < k){ 10 min = Math.abs(min) < Math.abs(target - num[i] - num[j] - num[k]) ? min : (target - num[i] - num[j] - num[k]); 11 if(num[j] + num[k] < goal) j ++; 12 else if(num[j] + num[k] > goal) k --; 13 else return target; 14 } 15 } 16 return target - min; 17 } 18 }