1 def append(self, p_object): # real signature unknown; restored from __doc__
2 """ L.append(object) -- append object to end """
3 pass
#1、练习(添加元素):
li = [11,22,33,"aabc","cddg",234,"alex",]
print(li)
aa = li.append(78) #在列表后添加列表元素,注意一次只能添加一个元素,否则报错
print(li)
#执行结果如下:
[11,22,33,"aabc","cddg",234,"alex",]
[11, 22, 33, 'aabc', 'cddg', 234, 'alex', 78]
1 def count(self, value): # real signature unknown; restored from __doc__
2 """ L.count(value) -> integer -- return number of occurrences of value """
3 return 0
1 #2、练习(计算列表元素出现个数)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 aa = li.count(33) #计算列表中指定元素出现的个数,一次只能计算一个元素
4 print(aa)
5 #执行结果如下:
6 2
1 def extend(self, iterable): # real signature unknown; restored from __doc__
2 """ L.extend(iterable) -- extend list by appending elements from the iterable """
3 pass
1 #3、练习(列表扩展(向后))
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 li.extend("kkk") #在列表后扩展,一次只能计算一个元素,字符串会拆分一个个显示
4 print(li)
5 li.extend(1234) #如果扩展整型数字会报错,数字不可拆分
6 print(li)
7 #执行结果:
8 [11, 22, 33, 'aabc', 'cddg', 33, 'alex', 'k', 'k', 'k']
9 报错:TypeError: 'int' object is not iterable
1 def index(self, value, start=None, stop=None): # real signature unknown; restored from __doc__
2 """
3 L.index(value, [start, [stop]]) -> integer -- return first index of value.
4 Raises ValueError if the value is not present.
5 """
6 return 0
1 #4、练习(找出列表元素索引位置)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 aa = li.index(22)
4 print(aa)
5 bb = li.index(33)
6 print(bb) #查找列表中元素的索引,重复存在则输出靠前的索引位置
7 #执行结果:
8 1
9 2
1 def insert(self, index, p_object): # real signature unknown; restored from __doc__
2 """ L.insert(index, object) -- insert object before index """
3 pass
1 #5、练习(插入元素)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 li.insert(1,"kkk") #根据列表下标位置,直接插入
4 print(li)
5 #执行结果:
6 [11, 'kkk', 22, 33, 'aabc', 'cddg', 33, 'alex']
1 def pop(self, index=None): # real signature unknown; restored from __doc__
2 """
3 L.pop([index]) -> item -- remove and return item at index (default last).
4 Raises IndexError if list is empty or index is out of range.
5 """
6 pass
1 #6、练习(取出元素)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 li.pop(3) #取出(删除)指定下标的元素
4 print(li)
5 li.pop() #如果不输入下标,则默认取出最后一个元素,注意:超出下标范围会报错
6 print(li)
7 #执行结果:
8 [11, 22, 33, 'cddg', 33, 'alex']
9 [11, 22, 33, 'cddg', 33]
1 def remove(self, value): # real signature unknown; restored from __doc__
2 """
3 L.remove(value) -- remove first occurrence of value.
4 Raises ValueError if the value is not present.
5 """
6 pass
1 #练习7、(移除元素)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 li.remove(33) #移除元素,如果有重复的,则移除靠前的那个
4 print(li)
5 #执行结果:
6 [11, 22, 'aabc', 'cddg', 33, 'alex']
1 def reverse(self): # real signature unknown; restored from __doc__
2 """ L.reverse() -- reverse *IN PLACE* """
3 pass
1 练习8、(翻转列表)
2 li = [11,22,33,"aabc","cddg",33,"alex",]
3 li.reverse() #翻转列表元素顺序
4 print(li)
5 #执行结果:
6 ['alex', 33, 'cddg', 'aabc', 33, 22, 11]
1 def sort(self, cmp=None, key=None, reverse=False): # real signature unknown; restored from __doc__
2 """
3 L.sort(cmp=None, key=None, reverse=False) -- stable sort *IN PLACE*;
4 cmp(x, y) -> -1, 0, 1
5 """
6 pass
#练习9、(列表重新排序)
#li = [11,22,33,"aabc","cddg",33,"alex",] 报错
# li.sort()
# print(li)
aa = ["kkk","bbb","jjj","www"] #列表按照ASCII码,重新排序,注意:列表里的元素只能全是字符串,或者全是数字,否则会报错
aa.sort()
print(aa)
#执行结果:
['bbb', 'jjj', 'kkk', 'www']