Django REST framework反向生成url

Django REST framework是一个基于Django的框架,REST framework又是怎么反向生成url的呢??

在前面的例子中,知道在REST framework中有6种版本控制的方式,进入任意一种版本控制的源码中,

class QueryParameterVersioning(BaseVersioning):
	"""
	GET /something/?version=0.1 HTTP/1.1
	Host: example.com
	Accept: application/json
	"""
	invalid_version_message = _('Invalid version in query parameter.')

	def determine_version(self, request, *args, **kwargs):
		version = request.query_params.get(self.version_param, self.default_version)
		if not self.is_allowed_version(version):
			raise exceptions.NotFound(self.invalid_version_message)
		return version

	def reverse(self, viewname, args=None, kwargs=None, request=None, format=None, **extra):
		url = super(QueryParameterVersioning, self).reverse(
			viewname, args, kwargs, request, format, **extra
		)
		if request.version is not None:
			return replace_query_param(url, self.version_param, request.version)
		return url

可以看到每一个版本控制的类中也都有reverse方法,由此可以了REST framework也是使用reverse的方式来反向生成url

新建一个Django项目,在项目的app中导入rest-framework

在settings.py文件中做如下配置

INSTALLED_APPS = [
	'django.contrib.admin',
	'django.contrib.auth',
	'django.contrib.contenttypes',
	'django.contrib.sessions',
	'django.contrib.messages',
	'django.contrib.staticfiles',
	'app01.apps.App01Config',
	'rest_framework',
]

REST_FRAMEWORK = {
	'DEFAULT_VERSIONING_CLASS': 'rest_framework.versioning.URLPathVersioning',
	'VERSION_PARAM': "version",
	'DEFAULT_VERSION': 'V1',
	'ALLOWED_VERSIONS': ['v1', 'v2']
}

在urls.py文件中添加路由信息

from django.conf.urls import url
from django.contrib import admin
from app01 import views

urlpatterns = [
	url(r'^admin/', admin.site.urls),
	url(r'^(?P<version>w+)/users/$',views.UsersView.as_view(),name="test1"),
]

在views.py文件中定义UserView的类

from django.shortcuts import render,HttpResponse
from rest_framework.views import APIView
from rest_framework.versioning import URLPathVersioning

class UsersView(APIView):

    def get(self,request,*args,**kwargs):
		
		# 打印版本信息
        print("request.version:",request.version)
		
		# reverse方法有一个viewname参数,在这里定义为urls.py中定义的name
        print(request.versioning_scheme.reverse("test1",request=request))

        return HttpResponse("aaaa")	

此时,在浏览器中输入http://127.0.0.1:8000/v1/users/,在服务端后台打印信息如下

request.version: v1
http://127.0.0.1:8000/v1/users/

再把浏览器中的url更换为http://127.0.0.1:8000/v2/users/,服务端后台的打印信息又变成了

request.version: v2
http://127.0.0.1:8000/v2/users/

可以看到打印出了正确的版本,并且反向生成url也已经成功了