lc 416 Partition Equal Subset Sum
416 Partition Equal Subset Sum
Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal.
Note:
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Each of the array element will not exceed 100.
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The array size will not exceed 200.
Example 1:
Input: [1, 5, 11, 5]
Output: true
Explanation: The array can be partitioned as [1, 5, 5] and [11].
Example 2:
Input: [1, 2, 3, 5]
Output: false
Explanation: The array cannot be partitioned into equal sum subsets.
DP Accepted
这其实是一个01背包问题,对于每一个数,我们可以选择放入和不放入,使dp[i][j]代表数组中前i个进行选择能否可以累计得到j。dp[0][0]为1,其余情况dp[i][j] = dp[i-1][j] || dp[i-1][j-nums[i]],因为要么不选择,那么就为dp[i-1][j],要么选择,那么就为dp[i-1][j-nums[i]]。
class Solution {
public:
bool canPartition(vector<int>& nums) {
int sum = accumulate(nums.begin(), nums.end(), 0);
if (sum & 1) return false;
int target = sum >> 1;
vector<int> dp(target + 1, 0);
dp[0] = 1;
for (auto num : nums)
for (int i = target; i >= num; i--)
dp[i] = dp[i] || dp[i-num];
return dp[target];
}
};