Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
动态规划即可,与Unique Path类似
1 class Solution { 2 public: 3 int minPathSum(vector<vector<int> > &grid) { 4 5 int m=grid.size(); 6 int n=grid[0].size(); 7 8 /* int **dp=new int *[m]; 9 for(int i=0;i<m;i++) 10 { 11 dp[i]=new int[n]; 12 } 13 */ 14 15 vector<vector<int>> dp(m,vector<int>(n)); 16 17 dp[0][0]=grid[0][0]; 18 19 for(int i=1;i<m;i++) 20 { 21 dp[i][0]=dp[i-1][0]+grid[i][0]; 22 } 23 24 for(int j=1;j<n;j++) 25 { 26 dp[0][j]=dp[0][j-1]+grid[0][j]; 27 } 28 29 for(int i=1;i<m;i++) 30 { 31 for(int j=1;j<n;j++) 32 { 33 dp[i][j]=grid[i][j]+min(dp[i-1][j],dp[i][j-1]); 34 } 35 } 36 37 return dp[m-1][n-1]; 38 39 } 40 };