题意:给出一个柱状图,各柱之间没有空隙。要求在这些柱覆盖的面积中画出一个最大的矩形(可跨越多个柱),求该矩形面积。
分析:用栈来维护一个严格升序序列,出栈时对元素的扩展面积进行计算,栈顶元素左右的扩展范围是,栈中的前一个元素的位置+1到当前读入元素的位置-1。
long long = int * int的时候第一个int要强制转换为long long。
View Code
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
usingnamespace std;
#define maxn 100005
struct polygon
{
int height, pos;
} stk[maxn];
int main()
{
//freopen("t.txt", "r", stdin);
int n, top;
longlong ans;
stk[0].pos =0;
while (scanf("%d", &n), n !=0)
{
top =0;
ans =0;
for (int i =1; i <= n; i++)
{
int a;
scanf("%d", &a);
while (top >0&& a <= stk[top].height)
{
if (ans < ((longlong) (i -1) - stk[top -1].pos)
* stk[top].height)
ans = ((longlong) (i -1) - stk[top -1].pos)
* stk[top].height;
top--;
}
top++;
stk[top].height = a;
stk[top].pos = i;
}
while (top >0)
{
if (ans < ((longlong) (n - stk[top -1].pos))
* (longlong) stk[top].height)
ans = ((longlong) (n - stk[top -1].pos))
* (longlong) stk[top].height;
top--;
}
printf("%lld\n", ans);
}
return0;
}
#include <cstdio>
#include <cstdlib>
#include <cstring>
usingnamespace std;
#define maxn 100005
struct polygon
{
int height, pos;
} stk[maxn];
int main()
{
//freopen("t.txt", "r", stdin);
int n, top;
longlong ans;
stk[0].pos =0;
while (scanf("%d", &n), n !=0)
{
top =0;
ans =0;
for (int i =1; i <= n; i++)
{
int a;
scanf("%d", &a);
while (top >0&& a <= stk[top].height)
{
if (ans < ((longlong) (i -1) - stk[top -1].pos)
* stk[top].height)
ans = ((longlong) (i -1) - stk[top -1].pos)
* stk[top].height;
top--;
}
top++;
stk[top].height = a;
stk[top].pos = i;
}
while (top >0)
{
if (ans < ((longlong) (n - stk[top -1].pos))
* (longlong) stk[top].height)
ans = ((longlong) (n - stk[top -1].pos))
* (longlong) stk[top].height;
top--;
}
printf("%lld\n", ans);
}
return0;
}