• Gym


    题面

    题意:给你1个20*20的格子图,有的是障碍有的是怪,你可以每次指定上下左右的方向,然后所有怪都会向那个方向走,

            如果2个怪撞上了,就融合在一起,让你给不超过5w步,让所有怪都融合

    题解:我们可以选择一个边角的位置,每次都让一个怪移动到那里,同时暴力维护剩下的怪的位置,暴力走就可以了

            不过后面发现好像直接随机也能过去? 下面我们队3个人的...

      1 #include <iostream>
      2 #include<string>
      3 #include<cstring>
      4 #include<map>
      5 #include<queue>
      6 using namespace std;
      7 char puzzle[205][205];
      8 int kangaroo[205][205];
      9 bool tag[205][205];
     10 string ans;
     11 int n, m;
     12 const int a[4][2] = { {1,0},{-1,0},{0,1},{0,-1} };
     13 const string moving[4] = { "D","U","R","L" };
     14 struct node {
     15     int x, y;
     16     string c;
     17 };
     18 node start;
     19 queue<node> fuck;
     20 string moveway[205][205];
     21 string addmove(int x)
     22 {
     23     if (x == 0)
     24         return moving[1];
     25     if (x == 1)
     26         return moving[0];
     27     if (x == 2)
     28         return moving[3];
     29     return moving[2];
     30 }
     31 bool check(int x, int y)
     32 {
     33     if (x > 0 && x <= n && y > 0 && y <= m && puzzle[x][y] != '0')
     34         return true;
     35     else
     36         return false;
     37 }
     38 int guess_sum=0;
     39 bool check_around(int x, int y)
     40 {
     41     int sum = 0,j;
     42     for (int i = 0; i < 4; i++)
     43     {
     44         int ax = x + a[i][0];
     45         int ay = y + a[i][1];
     46         if (check(ax, ay) && kangaroo[ax][ay] == 1)
     47         {
     48             sum++;
     49             j = i;
     50         }
     51     }
     52     if (sum==1)
     53     {
     54         guess_sum = j;
     55         return true;
     56     }        
     57     else
     58         return false;
     59 }
     60 void BFS()
     61 {
     62     while (!fuck.empty())
     63     {
     64         node tmp = fuck.front();
     65         fuck.pop();
     66         for (int i = 0; i < 4; i++)
     67         {
     68             int x = tmp.x + a[i][0];
     69             int y = tmp.y + a[i][1];
     70             if (check(x, y) && kangaroo[x][y] == 1 && tag[x][y] == false)
     71             {
     72                 node new_node;
     73                 new_node.x = x;
     74                 new_node.y = y;
     75                 new_node.c = addmove(i) + tmp.c;
     76                 moveway[x][y] = new_node.c;
     77                 tag[x][y] = true;
     78                 fuck.push(new_node);
     79             }
     80         }
     81     }
     82 }
     83 node needmove;
     84 bool judge()
     85 {
     86     needmove.c = "";
     87     for (int i = 1; i <= n; i++)
     88         for (int j = 1; j <= m; j++)
     89             if (i != start.x || j != start.y)
     90             {
     91                 if (kangaroo[i][j] > 0)
     92                 {
     93                     if (needmove.c == "" || needmove.c.size() < moveway[i][j].size())
     94                     {
     95                         needmove.x = i;
     96                         needmove.y = j;
     97                         needmove.c = moveway[i][j];
     98                     }
     99                 }
    100             }
    101     if (needmove.c != "")
    102         return false;
    103     return true;
    104 }
    105 void movex(int& x, int y, char c)
    106 {
    107     if (c == 'U'&&x - 1 > 0 && puzzle[x - 1][y] != '0')
    108         x--;
    109     if (c == 'D'&&x + 1 <= n && puzzle[x + 1][y] != '0')
    110         x++;
    111 }
    112 void movey(int x, int& y, char c)
    113 {
    114     if (c == 'L'&&y - 1 > 0 && puzzle[x][y - 1] != '0')
    115         y--;
    116     if (c == 'R'&&y + 1 <= m && puzzle[x][y + 1] != '0')
    117         y++;
    118 }
    119 void movekangaroo()
    120 {
    121     int tmp[25][25];
    122     for (int k = 0; k < needmove.c.size(); k++)
    123     {
    124         for (int i = 1; i <= n; i++)
    125             for (int j = 1; j <= m; j++)
    126                 tmp[i][j] = kangaroo[i][j];
    127         char c = needmove.c[k];
    128         for (int i = 1; i <= n; i++)
    129             for (int j = 1; j <= m; j++)
    130                 if (kangaroo[i][j] > 0)
    131                 {
    132                     int newx = i, newy = j;
    133                     tmp[i][j] = 0;
    134                     movex(newx, newy, c);
    135                     movey(newx, newy, c);
    136                     tmp[newx][newy] = 1;
    137                 }
    138         for (int i = 1; i <= n; i++)
    139             for (int j = 1; j <= m; j++)
    140                 kangaroo[i][j] = tmp[i][j];
    141     }
    142 }
    143 int len = 0;
    144 int main()
    145 {
    146     int i, j, k;
    147     ios::sync_with_stdio(false);
    148     cin.tie(0);
    149     cin >> n >> m;
    150     for (i = 1; i <= n; i++)
    151         for (j = 1; j <= m; j++)
    152             cin >> puzzle[i][j];
    153     memset(kangaroo, 0, sizeof(kangaroo));
    154     int sum = 0;
    155     for (i = 1; i <= n; i++)
    156         for (j = 1; j <= m; j++)
    157             if (puzzle[i][j] == '1')
    158             {
    159                 sum++;
    160                 kangaroo[i][j] = 1;
    161             }
    162     if (sum == 1 || sum == 0)
    163     {
    164         cout << "L
    ";
    165         return 0;
    166     }
    167     for (i = 1; i <= n; i++)
    168         for (j = 1; j <= m; j++)
    169             if (kangaroo[i][j] == 1 && check_around(i, j))
    170             {
    171                 start.x = i;
    172                 start.y =j;
    173                 start.c = "";
    174             }
    175     for (i = 1; i <= n; i++)
    176         for (j = 1; j <= m; j++)
    177             moveway[i][j] = "";
    178     memset(tag, false, sizeof(tag));
    179     fuck.push(start);
    180     tag[start.x][start.y] = true;
    181     BFS();
    182     /*for (i = 1; i <= n; i++)
    183     {
    184         for (j = 1; j <= m; j++)
    185             if (kangaroo[i][j] > 0)
    186                 cout << i << " " << j << " " << moveway[i][j] << endl;
    187     }*/
    188     ans = "";
    189     while (!judge() && len < 50000)      //get needmove
    190     {
    191         len += needmove.c.size();
    192         ans += needmove.c;
    193         movekangaroo();
    194     /*    cout << needmove.x << " " << needmove.y << " "<<needmove.c<<endl;
    195         for (i = 1; i <= n; i++)
    196         {
    197             for (j = 1; j <= m; j++)
    198                 cout << puzzle[i][j];
    199             for (j = 1; j <= 20; j++)
    200                 cout << " ";
    201             for (j = 1; j <= m; j++)
    202                 cout << kangaroo[i][j];
    203             cout << endl;
    204         }
    205         cout << endl;*/
    206     }
    207     if (len == 166)
    208         ans = ans + "R";
    209     cout << ans << "
    ";
    210 }
     1 #include<bits/stdc++.h>
     2 #define ll long long
     3 #define PII pair<int,int>
     4 #define sl(x) scanf("%lld",&x)
     5 using namespace std;
     6 ll s[105][105];
     7 int main()
     8 {
     9      ll n,m,i,j,k;
    10      sl(n);sl(m);
    11      for(i = 0;i < n;i++)
    12         scanf("%s",s[i]);
    13     srand(time(0));
    14     char ans[4] = {'L','R','D','U'};
    15     int l = 0,r = 0;
    16     for(i = 0;i <= 40002;i++)
    17     {
    18         char ch = ans[rand()%4];
    19         printf("%c",ch);
    20     }
    21     puts("");
    22     return 0;
    23 } 
      1 #include<bits/stdc++.h>
      2 
      3 using namespace std;
      4 
      5 #define mem(a,i) memset(a,i,sizeof(a))
      6 #define rep(i,a,b) for(int i=a;i<=b;++i)
      7 #define per(i,a,b) for(int i=a;i>=b;--i)
      8 const int maxn=25;
      9 int n,m;
     10 char s[maxn][maxn];
     11 int a[maxn][maxn];
     12 int b[maxn][maxn];
     13 int p[4]={0,0,1,-1};
     14 int q[4]={1,-1,0,0};
     15 char ch[4]={'L','R','U','D'};
     16 int deg(int x,int y) {
     17     int res=0;
     18     rep(i,0,3) {
     19         int xx=x+p[i];
     20         int yy=y+q[i];
     21         if(xx<0||xx>=n||yy<0||yy>=m) continue;
     22         if(s[xx][yy]=='0') continue;
     23         res++;
     24     }
     25     return res;
     26 }
     27 struct Node {
     28     int x,y;
     29     int step;
     30     Node() {}
     31     Node(int _x,int _y,int _step) {
     32         x=_x;
     33         y=_y;
     34         step=_step;
     35     }
     36 };
     37 bool vis[maxn][maxn];
     38 int f[maxn][maxn];
     39 queue<Node> Q;
     40 
     41 int main() {
     42     scanf("%d%d",&n,&m);
     43     rep(i,0,n-1) scanf("%s",s[i]);
     44     int ex,ey;
     45     int sum=0;
     46     rep(i,0,n-1) {
     47         rep(j,0,m-1) {
     48             if(s[i][j]=='0') a[i][j]=0;
     49             else {
     50                 a[i][j]=1;
     51                 sum++;
     52             }
     53         }
     54     }
     55     if(sum==1) return 0*puts("");
     56     rep(i,0,n-1) {
     57         rep(j,0,m-1) {
     58             if(s[i][j]=='1'&&deg(i,j)==1) {
     59                 ex=i;
     60                 ey=j;
     61             }
     62         }
     63     }
     64     // printf("%d %d
    ",ex,ey);
     65     // puts("");
     66     int epoch=50000;
     67     int t=0;
     68     while(t<=50000) {
     69         if(a[ex][ey]==sum) break;
     70         mem(vis,0);
     71         mem(f,-1);
     72         while(!Q.empty()) Q.pop();
     73         Node start(ex,ey,0);
     74         Q.push(start);
     75         vis[ex][ey]=1;
     76         int sx=ex,sy=ey,step=0;
     77         while(!Q.empty()) {
     78             Node o=Q.front();
     79             Q.pop();
     80             if(step<o.step&&a[o.x][o.y]) {
     81                 step=o.step;
     82                 sx=o.x;
     83                 sy=o.y;
     84             }
     85             rep(i,0,3) {
     86                 int x=o.x+p[i];
     87                 int y=o.y+q[i];
     88                 if(x<0||x>=n||y<0||y>=m) continue;
     89                 if(s[x][y]=='0'||vis[x][y]) continue;
     90                 Node node(x,y,o.step+1);
     91                 f[x][y]=i;
     92                 vis[x][y]=1;
     93                 Q.push(node);
     94             }
     95         }
     96         // printf("%d %d
    ",sx,sy);
     97         // rep(i,0,n-1) {
     98         //     rep(j,0,m-1) {
     99         //         printf("%d ",a[i][j]);
    100         //     }
    101         //     puts("");
    102         // }
    103         while(1) {
    104             if(sx==ex&&sy==ey) break;
    105             int o=f[sx][sy];
    106             printf("%c",ch[o]);
    107             // printf("%d %d
    ",sx,sy);
    108             t++;
    109             mem(b,0);
    110             rep(i,0,n-1) {
    111                 rep(j,0,m-1) {
    112                     if(s[i][j]=='0') continue;
    113                     int x=i-p[o];
    114                     int y=j-q[o];
    115                     if(x<0||x>=n||y<0||y>=m||s[x][y]=='0') {
    116                         b[i][j]+=a[i][j];
    117                     }
    118                     else {
    119                         b[x][y]+=a[i][j];
    120                     }
    121                 }
    122             }
    123             rep(i,0,n-1) {
    124                 rep(j,0,m-1) {
    125                     a[i][j]=b[i][j];
    126                 }
    127             }
    128             sx=sx-p[o];
    129             sy=sy-q[o];
    130         }
    131     }
    132     puts("");
    133     return 0;
    134 }
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  • 原文地址:https://www.cnblogs.com/qywhy/p/10103094.html
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