成段更新:
#include <cstdio> #include <algorithm> using namespace std; #define LL long long #define lson l , m , rt << 1 #define rson m + 1 , r , rt << 1 | 1 const int maxn = 111111; LL addv[maxn<<2]; LL sumv[maxn<<2]; //int maxv[maxn<<2]; void PushUp(int rt) { // maxv[rt] = max(maxv[rt<<1], maxv[rt<<1|1]); sumv[rt] = sumv[rt<<1] + sumv[rt<<1|1]; } void PushDown(int rt,int m) { if (addv[rt]) { addv[rt<<1] += addv[rt]; addv[rt<<1|1] += addv[rt]; sumv[rt<<1] += addv[rt] * (m - (m >> 1)); sumv[rt<<1|1] += addv[rt] * (m >> 1); // maxv[rt<<1] += addv[rt]; // maxv[rt<<1|1] += addv[rt]; addv[rt] = 0; } } void build(int l,int r,int rt) { addv[rt] = 0; if (l == r) { scanf("%I64d",&sumv[rt]); //scanf("%d", &maxv[rt]); return ; } int m = (l + r) >> 1; build(lson); build(rson); PushUp(rt); } void update(int L,int R,int c,int l,int r,int rt) { if (L <= l && r <= R) { addv[rt] += c; sumv[rt] += (LL)c * (r - l + 1); //maxv[rt] += c return ; } PushDown(rt , r - l + 1); int m = (l + r) >> 1; if (L <= m) update(L , R , c , lson); if (m < R) update(L , R , c , rson); PushUp(rt); } LL query(int L,int R,int l,int r,int rt) { if (L <= l && r <= R) { //return maxv[rt]; return sumv[rt]; } PushDown(rt , r - l + 1); int m = (l + r) >> 1; LL ret = 0; if (L <= m) ret += query(L, R, lson); //ret = max(ret, query(L , R , lson)); if (m < R) ret += query(L, R, rson); //ret = max(ret, query(L , R , rson)); return ret; } int main() { int N , Q; scanf("%d%d",&N,&Q); build(1 , N , 1); while (Q --) { char op[2]; int a , b , c; scanf("%s",op); if (op[0] == 'Q') { scanf("%d%d",&a,&b); printf("%I64d ",query(a , b , 1 , N , 1)); } else { scanf("%d%d%d",&a,&b,&c); update(a , b , c , 1 , N , 1); } } return 0; }
成段置值:
#include <cstdio> #include <algorithm> using namespace std; #define lson l , m , rt << 1 #define rson m + 1 , r , rt << 1 | 1 const int maxn = 111111; int h , w , n; int col[maxn<<2]; int sum[maxn<<2]; void PushUp(int rt) { sum[rt] = sum[rt<<1] + sum[rt<<1|1]; } void PushDown(int rt,int m) { if (col[rt]) { col[rt<<1] = col[rt<<1|1] = col[rt]; sum[rt<<1] = (m - (m >> 1)) * col[rt]; sum[rt<<1|1] = (m >> 1) * col[rt]; col[rt] = 0; } } void build(int l,int r,int rt) { col[rt] = 0; sum[rt] = 1; if (l == r) return ; int m = (l + r) >> 1; build(lson); build(rson); PushUp(rt); } int query(int L,int R,int l,int r,int rt) {//求和写法,参数信息=>(问询区间左端点,问询区间右端点,总区间左端点,总区间右端点,根节点编号) if (L <= l && r <= R) { return sumv[rt]; } int m = l + ((r - l)>>1); int ret = 0; if (L <= m) ret += query(L , R , lson); if (R > m) ret += query(L , R , rson); return ret; } void update(int L,int R,int c,int l,int r,int rt) { if (L <= l && r <= R) { col[rt] = c; sum[rt] = c * (r - l + 1); return ; } PushDown(rt , r - l + 1); int m = (l + r) >> 1; if (L <= m) update(L , R , c , lson); if (R > m) update(L , R , c , rson); PushUp(rt); } int main() { int T , n , m; scanf("%d",&T); for (int cas = 1 ; cas <= T ; cas ++) { scanf("%d%d",&n,&m); build(1 , n , 1); while (m --) { int a , b , c; scanf("%d%d%d",&a,&b,&c); update(a , b , c , 1 , n , 1); } printf("Case %d: The total value of the hook is %d. ",cas , sum[1]); } return 0; }
单点更新:
/* 说明: 此模板支持对于线段的单点加减操作更新、区间最值or和的查询 下面主要以求和操作为例,注释部分为求最值功能,根据自己的 需求适当修改模板 验证题目:HDU 1166 敌兵布阵 (以下代码也是解决此题的代码) */ #include <cstdio> #include <algorithm> #include <string.h> using namespace std; #define lson l , m , rt << 1 #define rson m + 1 , r , rt << 1 | 1 const int maxn = 50005;//maxn = 线段的最大长度 则=> maxn<<2 = 线段树可能的最多结点 //int maxv[maxn<<2];//保存最大值 //int minv[maxn<<2];//保存最小值 int sumv[maxn<<2];//保存区间和 void PushUP(int rt) { //maxv[rt] = max(maxv[rt<<1] , maxv[rt<<1|1]); //minv[rt] = min(minv[rt<<1], minv[rt<<1|1]); sumv[rt] = sumv[rt<<1] + sumv[rt<<1|1]; } void build(int l,int r,int rt) {//设置初始值 if (l == r) { // scanf("%d",&maxv[rt]); // scanf("%d", &minv[rt]); scanf("%d", &sumv[rt]); return ; } int m = l + ((r - l)>>1); build(lson); build(rson); PushUP(rt); } void update(int p,int sc,int l,int r,int rt) {//单点更新,参数(更新点,更新值,总区间左端点,总区间右端点,根节点编号) if (l == r) { //maxv[rt] = sc; //minv[rt] = sc; sumv[rt] += sc; return ; } int m = l + ((r - l)>>1); if (p <= m) update(p , sc , lson); else update(p , sc , rson); PushUP(rt); } // int query(int L,int R,int l,int r,int rt) {//查询最大值的写法、最小值同理、求和区间写法在下面 // if (L <= l && r <= R) { // return maxv[rt]; // } // int m = (l + r) >> 1; // int ret = 0; // if (L <= m) ret = max(ret , query(L , R , lson)); // if (R > m) ret = max(ret , query(L , R , rson)); // return ret; // } int query(int L,int R,int l,int r,int rt) {//求和写法,参数信息=>(问询区间左端点,问询区间右端点,总区间左端点,总区间右端点,根节点编号) if (L <= l && r <= R) { return sumv[rt]; } int m = l + ((r - l)>>1); int ret = 0; if (L <= m) ret += query(L , R , lson); if (R > m) ret += query(L , R , rson); return ret; } int main(void) { int nCase; scanf("%d", &nCase); for(int t = 1; t <= nCase; t++){ memset(sumv, 0, sizeof(sumv)); int len; scanf("%d", &len); build(1, len, 1); char s[20]; printf("Case %d: ", t); while(~scanf("%s", s) && s[0] != 'E'){//s != 'End' if(s[0] == 'Q'){//s = Query int L, R; scanf("%d %d", &L, &R); printf("%d ", query(L, R, 1, len, 1)); } else if(s[0] == 'S'){//减操作 int point, val; scanf("%d%d", &point, &val); update(point, -val, 1, len, 1); } else if(s[0] == 'A'){//加操作 int point, val; scanf("%d%d", &point, &val); update(point, val, 1, len, 1); } } } return 0; }
融合置值和成段加减 ( 刘汝佳程序 ) :
#include<bits/stdc++.h> #define LL long long #define lson l, m, rt<<1 #define rson m+1, r, rt<<1|1 using namespace std; const int maxn = 1e5 + 10; const int maxnode = maxn<<2; struct IntervalTree { LL _sum, _min, _max; LL sumv[maxnode], minv[maxnode], maxv[maxnode], setv[maxnode], addv[maxnode]; void maintain(int L, int R, int rt) { int lc = rt<<1, rc = rt<<1|1; if(R > L) { sumv[rt] = sumv[lc] + sumv[rc]; minv[rt] = min(minv[lc], minv[rc]); maxv[rt] = max(maxv[lc], maxv[rc]); } if(setv[rt] >= 0) { minv[rt] = maxv[rt] = setv[rt]; sumv[rt] = setv[rt] * (R-L+1); } if(addv[rt]) { minv[rt] += addv[rt]; maxv[rt] += addv[rt]; sumv[rt] += addv[rt] * (R-L+1); } } void pushdown(int rt) { int lc = rt*2, rc = rt*2+1; if(setv[rt] >= 0) { setv[lc] = setv[rc] = setv[rt]; addv[lc] = addv[rc] = 0; setv[rt] = -1; } if(addv[rt]) { addv[lc] += addv[rt]; addv[rc] += addv[rt]; addv[rt] = 0; } } ///update(更新区间左右端点、更新值、更新选项 op = 1 为加减 op != 1 为置值、当前区间左右端点、根) void update(int L, int R, LL v, int op, int l, int r, int rt){ int lc = rt<<1, rc = rt<<1|1; if(L <= l && R >= r) { if(op == 1) addv[rt] += v; else { setv[rt] = v; addv[rt] = 0; } } else { pushdown(rt); int m = l + (r-l)/2; if(L <= m) update(L, R, v, op, lson); else maintain(lson); if(R > m) update(L, R, v, op, rson); else maintain(rson); } maintain(l, r, rt); } ///query(问询的左右端点、累加lazy_tag的累加量、当前区间左右端点、根) void query(int L, int R, LL add, int l, int r, int rt) { if(setv[rt] >= 0) { LL v = setv[rt] + add + addv[rt]; _sum += v * (LL)(min(r,R)-max(l,L)+1); _min = min(_min, v); _max = max(_max, v); } else if(L <= l && R >= r) { _sum += sumv[rt] + add * (LL)(r-l+1); _min = min(_min, minv[rt] + add); _max = max(_max, maxv[rt] + add); } else { int m = l + (r-l)/2; if(L <= m) query(L, R, add+addv[rt], lson); if(R > m) query(L, R, add+addv[rt], rson); } } }T; int main(void) { int n, q; scanf("%d %d", &n, &q); for(int i=1; i<=n; i++){ LL v; scanf("%lld", &v); T.update(i, i, v, 1, 1, n, 1); } while(q--){ int type; scanf("%d", &type); if(type == 1){ int pos; scanf("%d", &pos); LL v; scanf("%lld", &v); T.update(pos, pos, v, 2, 1, n, 1); }else if(type == 2){ LL v; scanf("%lld", &v); T.update(1, n, v, 1, 1, n, 1); }else{ int pos; scanf("%d", &pos); T._sum = 0; T.query(pos, pos, 0, 1, n, 1); printf("%lld ", T._sum); } } return 0; }
此程序是这题 ==> 戳这里 的代码、可以验模板正确性