题目描述
Given a linked list, determine if it has a cycle in it.
Follow up:Can you solve it without using extra space?
解题思路:使用快慢指针,若在遍历过程中slow==fast则有环,否则无环
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 bool hasCycle(ListNode *head) { 12 if(head == NULL)//记得空链表处理 13 return false; 14 ListNode *pSlow = head; 15 ListNode *pFast = head; 16 while(pFast->next != NULL && pFast->next->next != NULL) 17 { 18 19 pSlow = pSlow->next; 20 pFast = pFast->next->next; 21 if(pSlow == pFast)//一定要移动完再判断 22 return true; 23 } 24 return false; 25 26 } 27 };