Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

https://leetcode.com/problems/compare-version-numbers/

public class Solution 
{
    public static int compareVersion(String version1, String version2)
    {
        String[]t1=version1.split("\.");
        String[]t2=version2.split("\.");
        int[]v1=new int[t1.length];
        int[]v2=new int[t2.length];
        for(int i=0;i<v1.length;i++)
            v1[i]=Integer.parseInt(t1[i]);
        for(int i=0;i<v2.length;i++)
            v2[i]=Integer.parseInt(t2[i]);
        for(int i=0;i<v1.length&&i<v2.length;i++)
        {
             if(v1[i]>v2[i])
                 return 1;
             else if(v1[i]<v2[i])
                 return -1;
             else
                 ;
        }
        if(v1.length>v2.length)
        {
            for(int i=v2.length;i<v1.length;i++)
                if(v1[i]!=0)
                    return 1;
            return 0;
        }
        else if(v1.length<v2.length)
        {
            for(int i=v1.length;i<v2.length;i++)
                if(v2[i]!=0)
                    return -1;
            return 0;
        }
        else
            return 0;
        
    }
    public static void main(String args[])
    {
        String version1="1";
        String version2="1.1";
        String[] t=version1.split("\.");
        System.out.println(compareVersion(version1,version2));
    }
}