Reverse Integer

Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

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Have you thought about this?

Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Update (2014-11-10):
Test cases had been added to test the overflow behavior.

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其他人解法：https://leetcode.com/discuss/questions/oj/reverse-integer?sort=hot

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public class Solution 
{
    // you need treat n as an unsigned value
    public static int reverse(int x) 
    {
        
        long y=0;
        int n=0;
        y=x;
        for(int i=0;i<31;i++)
        {
            if(y%10!=0)
                n=i+1;
            y=y/10;    
        }
        y=0;
        for(int i=0;i<n;i++)
        {
               y=y*10;
            y=y+x%10;
            x=x/10;
        }
        int maxnum=(int) (Math.pow(2, 31)-1);
        int minnum=(int) (-Math.pow(2, 31));
//        System.out.println(maxnum);
//        System.out.println(minnum);
        if(y>maxnum||y<minnum)
            y=0;
        return (int)y;
    }
    public static void main(String args[])
    {
        System.out.println(reverse(1534236469));
    }
}