• SZU5


    A - Couple doubi

    这种题不要想复杂,直接找规律。找不出规律就打表找规律

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define INF 10000
    #define MAXN 5010
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    
    int k,p;
    
    int main()
    {
         int i,j,kase=0;
         while(sf("%d%d",&k,&p)==2)
         {
                if(k/(p-1)%2==1) pf("YES
    ");
                else pf("NO
    ");
         }
    }

    B - ZCC Loves Codefires

    贪心

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define INF 10000
    #define MAXN 5010
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    
    int n;
    
    struct node
    {
        int t,a;
        double f;
    }p[100005];
    
    int cmp(const node& x,const node& y)
    { return x.f<y.f;}
    
    int main()
    {
         int i,j,kase=0;
         while(sf("%d",&n)==1)
         {
                for(i=0;i<n;i++)
                  sf("%d",&p[i].t);
                for(i=0;i<n;i++)
                {
                  sf("%d",&p[i].a);
                  p[i].f = (double)p[i].t/p[i].a;
                }
                sort(p,p+n,cmp);
    
                long long sumt=0,res=0;
    
                for(i=0;i<n;i++)
                {
                    sumt+=p[i].t;
                    res+=p[i].a*sumt;
                }
                pf("%I64d
    ",res);
         }
    }

    C - Magical Forest(HDU 4941)

    双重MAP

    D - Task

    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #include <queue>
    #include <vector>
    #include <set>
    #include <map>
    typedef __int64 ll;
    const int N=100005;
    using namespace std;
    struct node
    {
        int x,y;
    }machine[N],tesk[N];
    bool cmp(node a,node b)
    {
        if(a.x==b.x)
            return a.y>b.y;
        return a.x>b.x;
    }
    int main()
    {
        int n,m,i,j,k,num;
        ll money;
        int temp[105];
        while(~scanf("%d%d",&n,&m))
        {
            for(i=0;i<n;i++)
                scanf("%d%d",&machine[i].x,&machine[i].y);
            for(i=0;i<m;i++)
                scanf("%d%d",&tesk[i].x,&tesk[i].y);
            sort(machine,machine+n,cmp);
            sort(tesk,tesk+m,cmp);
            memset(temp,0,sizeof(temp));
            for(i=0,j=0,money=0,num=0;i<m;i++)
            {
                while(machine[j].x>=tesk[i].x&&j<n)//标记符合时间条件的机器
                {
                    temp[machine[j].y]++;
                    j++;
                }
                for(k=tesk[i].y;k<=100;k++)//判断是否有能完成测试的机器
                {
                    if(temp[k])
                    {
                        temp[k]--;
                        num++;
                        money=money+500*tesk[i].x+2*tesk[i].y;
                        break;
                    }
                }
            }
            printf("%d %I64d
    ",num,money);
        }
        return 0;
    }

    E - Stupid Tower Defense

    dp,分析见:http://blog.csdn.net/u012860063/article/details/38520673

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <cctype>
    #include <vector>
    #include <iterator>
    #include <set>
    #include <map>
    #include <sstream>
    using namespace std;
    
    #define mem(a,b) memset(a,b,sizeof(a))
    #define pf printf
    #define sf scanf
    #define spf sprintf
    #define pb push_back
    #define debug printf("!
    ")
    #define INF 10000
    #define MAXN 5010
    #define MAX(a,b) a>b?a:b
    #define blank pf("
    ")
    #define LL long long
    #define ALL(x) x.begin(),x.end()
    #define INS(x) inserter(x,x.begin())
    #define pqueue priority_queue
    
    LL dp[1510][1510];
    
    int main()
    {
         int i,j,kase=0,T;
         sf("%d",&T);
         while(T--)
         {
            LL n,x,y,z,t;
            sf("%I64d%I64d%I64d%I64d%I64d",&n,&x,&y,&z,&t);
    
            LL ans = n*x*t;
    
            for(i=1;i<=n;i++)
              {
                   for(j=0;j<=i;j++)
                   {
                        if(j==0)
                             dp[i][j] = dp[i-1][j]+(i-1)*y*t;
                        else
                             dp[i][j] = max(dp[i-1][j]+(i-j-1)*y*(t+z*j),
                                            dp[i-1][j-1]+(i-j)*y*(t+z*(j-1)));
                        ans = max(ans,dp[i][j]+(n-i)*(x+y*(i-j))*(t+z*j));
                   }
              }
              pf("Case #%d: %I64d
    ",++kase,ans);
    
         }
    }
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  • 原文地址:https://www.cnblogs.com/qlky/p/5296541.html
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