Ladies and gentlemen, please sit up straight.
Don't tilt your head. I'm serious.
For nn given strings S1,S2,⋯,SnS1,S2,⋯,Sn, labelled from 11 to nn, you should find the largest i (1≤i≤n)i (1≤i≤n)such that there exists an integer j (1≤j<i)j (1≤j<i) and SjSj is not a substring of SiSi.
A substring of a string SiSi is another string that occurs in SiSi. For example, ``ruiz" is a substring of ``ruizhang", and ``rzhang" is not a substring of ``ruizhang".
Don't tilt your head. I'm serious.
For nn given strings S1,S2,⋯,SnS1,S2,⋯,Sn, labelled from 11 to nn, you should find the largest i (1≤i≤n)i (1≤i≤n)such that there exists an integer j (1≤j<i)j (1≤j<i) and SjSj is not a substring of SiSi.
A substring of a string SiSi is another string that occurs in SiSi. For example, ``ruiz" is a substring of ``ruizhang", and ``rzhang" is not a substring of ``ruizhang".
InputThe first line contains an integer t (1≤t≤50)t (1≤t≤50)which is the number of test cases.
For each test case, the first line is the positive integer n (1≤n≤500)n (1≤n≤500) and in the following nn lines list are the strings S1,S2,⋯,SnS1,S2,⋯,Sn.
All strings are given in lower-case letters and strings are no longer than 20002000 letters.OutputFor each test case, output the largest label you get. If it does not exist, output −1−1.Sample Input
4 5 ab abc zabc abcd zabcd 4 you lovinyou aboutlovinyou allaboutlovinyou 5 de def abcd abcde abcdef 3 a ba ccc
Sample Output
Case #1: 4 Case #2: -1 Case #3: 4 Case #4: 3
这题用hash预处理 然后用vector从上到下扫过去
类似于维护当前未匹配的序列
1 #include <cstdio> 2 #include <cstring> 3 #include <queue> 4 #include <cmath> 5 #include <algorithm> 6 #include <set> 7 #include <iostream> 8 #include <map> 9 #include <stack> 10 #include <string> 11 #include <vector> 12 #define pi acos(-1.0) 13 #define eps 1e-6 14 #define fi first 15 #define se second 16 #define lson l,m,rt<<1 17 #define rson m+1,r,rt<<1|1 18 #define bug printf("****** ") 19 #define mem(a,b) memset(a,b,sizeof(a)) 20 #define fuck(x) cout<<"["<<x<<"]"<<endl 21 #define sf(n) scanf("%d", &n) 22 #define sff(a,b) scanf("%d %d", &a, &b) 23 #define sfff(a,b,c) scanf("%d %d %d", &a, &b, &c) 24 #define sffff(a,b,c,d) scanf("%d %d %d %d", &a, &b, &c, &d) 25 #define pf printf 26 #define FRE(i,a,b) for(i = a; i <= b; i++) 27 #define FREE(i,a,b) for(i = a; i >= b; i--) 28 #define FRL(i,a,b) for(i = a; i < b; i++) 29 #define FRLL(i,a,b) for(i = a; i > b; i--) 30 #define FIN freopen("DATA.txt","r",stdin) 31 #define gcd(a,b) __gcd(a,b) 32 #define lowbit(x) x&-x 33 #pragma comment (linker,"/STACK:102400000,102400000") 34 using namespace std; 35 typedef long long LL; 36 typedef unsigned long long ULL; 37 const int INF = 0x7fffffff; 38 const int maxn = 5e4 + 10; 39 ULL HASH[505], seed = 133331, p[2010], mp[505][2010]; 40 char s2[2010],a[505][2020]; 41 int t, n; 42 void init() { 43 p[0] = 1; 44 for (int i = 1 ; i <= 2010 ; i++) 45 p[i] = p[i - 1] * seed; 46 } 47 int check(int i, int j) { 48 int len1 = strlen(a[i]), len2 = strlen(a[j]); 49 for (int k = 0 ; k <= len1 - len2 ; k++){ 50 if (mp[i][k + len2] - mp[i][k]*p[len2] == HASH[j]) return 1; 51 } 52 return 0; 53 } 54 int main() { 55 init(); 56 int cas=1; 57 sf(t); 58 while(t--) { 59 sf(n); 60 for (int i = 1 ; i <= n ; i++) { 61 scanf("%s", a[i]); 62 int len = strlen(a[i]); 63 int top = 0; 64 mp[i][0] = 0; 65 for (int j = 0 ; j < len ; j++) { 66 s2[top++] = a[i][j]; 67 mp[i][top] = mp[i][top - 1] * seed + a[i][j]; 68 } 69 HASH[i] = mp[i][top]; 70 } 71 int ans=-1; 72 vector<int>s; 73 s.clear(); 74 s.push_back(1); 75 for (int i=2 ;i<=n ;i++) { 76 while(s.size()) { 77 if ( check(i,s[s.size()-1]) ) s.pop_back(); 78 else break; 79 } 80 s.push_back(i); 81 if (s.size()>1) ans=i; 82 } 83 printf("Case #%d: %d ",cas++,ans); 84 } 85 return 0; 86 }