• Python识别图片条形码并框选


    感谢http://blog.jobbole.com/80448/ 提供参考,并将他的代码转到Pycharm中

    import numpy as np
    import cv2

    # load the image and convert it to grayscale
    image = cv2.imread('./pic/cde.jpg')
    gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)

    # compute the Scharr gradient magnitude representation of the images
    # in both the x and y direction
    gradX = cv2.Sobel(gray, ddepth = cv2.cv2.CV_32F, dx = 1, dy = 0, ksize = -1)
    gradY = cv2.Sobel(gray, ddepth = cv2.cv2.CV_32F, dx = 0, dy = 1, ksize = -1)

    # subtract the y-gradient from the x-gradient
    gradient = cv2.subtract(gradX, gradY)
    gradient = cv2.convertScaleAbs(gradient)

    # blur and threshold the image
    blurred = cv2.blur(gradient, (9, 9))
    (_, thresh) = cv2.threshold(blurred, 225, 255, cv2.THRESH_BINARY)

    # construct a closing kernel and apply it to the thresholded image
    kernel = cv2.getStructuringElement(cv2.MORPH_RECT, (21, 7))
    closed = cv2.morphologyEx(thresh, cv2.MORPH_CLOSE, kernel)

    # perform a series of erosions and dilations
    closed = cv2.erode(closed, None, iterations = 4)
    closed = cv2.dilate(closed, None, iterations = 4)

    # find the contours in the thresholded image, then sort the contours
    # by their area, keeping only the largest one
    (cnts, _) = cv2.findContours(closed.copy(), cv2.RETR_EXTERNAL,
    cv2.CHAIN_APPROX_SIMPLE)
    c = sorted(cnts, key = cv2.contourArea, reverse = True)[0]

    # compute the rotated bounding box of the largest contour
    rect = cv2.minAreaRect(c)
    box = np.int0(cv2.boxPoints(rect))

    # draw a bounding box arounded the detected barcode and display the
    # image
    cv2.drawContours(image, [box], -1, (0, 255, 0), 3)
    cv2.imshow("Image", image)
    cv2.waitKey(0)
  • 相关阅读:
    HTML--1标签表格
    HTML--4格式布局
    HTML--3css样式表
    快速制作网页的方法
    表单
    表单练习——邮箱注册
    斐波那契数列
    0125 多线程 继承Thread 练习
    Hash(哈希)
    [COI2007] [luogu P1823] Patrik 音乐会的等待 解题报告 (单调栈)
  • 原文地址:https://www.cnblogs.com/qiuya/p/10853392.html
Copyright © 2020-2023  润新知