有进度条的圆周率计算

from random import random
import time
from time import perf_counter
darts=10000*10000
hits=0.0
scale=10
start=perf_counter()
for j in range(scale+1):
    a='*'*j
    b='.'*(scale-j)
    c=(j/scale)*100
    dur=time.perf_counter()-start
    print("{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,dur))
    time.sleep(0.1)
for i in range(1,darts+1):
    x,y=random(),random()
    dist=pow(x**2+y**2,0.5)
    if dist<=1.0:
        hits=hits+1 
    pi=4*(hits/darts)
print("/n"+"圆周率的值是{}".format(pi))