1 double Solution::findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) 2 { 3 if (nums1.size() > nums2.size()) 4 { 5 return findMedianSortedArrays(nums2, nums1); 6 } 7 8 int m = nums1.size(); 9 int n = nums2.size(); //m <= n 10 11 int left = 0, right = m, ansi=-1; 12 int midNum1 = 0, midNum2 = 0; 13 auto max = [](int a, int b) 14 { 15 return a >= b ? a : b; 16 }; 17 auto min = [](int a, int b) 18 { 19 return a <= b ? a : b; 20 }; 21 while (left <= right) 22 { 23 int i = (left + right) / 2; 24 int j = (m + n + 1) / 2 - i; 25 26 int i_1 = i == 0 ? INT_MIN : nums1[i - 1]; 27 int i_0 = i == m ? INT_MAX : nums1[i]; 28 29 int j_1 = j == 0 ? INT_MIN : nums2[j - 1]; 30 int j_0 = j == n ? INT_MAX : nums2[j]; 31 if (i_1 <= j_0) 32 { 33 ansi = i; 34 midNum1 = max(i_1, j_1); 35 midNum2 = min(i_0, j_0); 36 left = i + 1; 37 } 38 else 39 { 40 right = i - 1; 41 } 42 } 43 return (1 == (m + n) % 2) ? (double)midNum1 : (double)(midNum1 + midNum2) / 2; 44 }