zoj 2744 Palindromes

Palindromes

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Time Limit: 2 Seconds      Memory Limit: 65536 KB

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A regular palindrome is a string of numbers or letters that is the same forward as backward. For example, the string "ABCDEDCBA" is a palindrome because it is the same when the string is read from left to right as when the string is read from right to left.

Now give you a string S, you should count how many palindromes in any consecutive substring of S.

Input

There are several test cases in the input. Each case contains a non-empty string which has no more than 5000 characters.

Proceed to the end of file.

Output

A single line with the number of palindrome substrings for each case.

Sample Input

aba
aa

Sample Output

4
3

题意：求一个串的所有回文字串的个数，这里要讨论串是奇数串还是偶数串，我的处理办法是将其变成奇数串，详细见代码。

#include <iostream>
#include <string>
#include <cstdio>
using namespace std;
int main(){
    string s1, s2 = "#";
    int left, right, count;
    while(cin >> s1){
        s2 = "#";
        int len1 = s1.length();
        //将串变成奇数串，避免分情况讨论，以前学习求最长回文字串的一个算法，看到的处理办法，挺好的 
        for(int i = 0; i < len1; i++){
            s2 += s1[i];
            s2 += '#';
        }
        int len2 = s2.length();
        count = len1;//每个字符本身都算一个回文串 
        for(int i = 1; i < len2 - 1; i++){
            left = i - 1;
            right = i + 1;
            //中心向外扩散，一遇到不是回文串，那么再向外扩散的串都不是回文串 
            while(left >= 0 && right < len2 && s2[left] == s2[right]){
                if(s2[left] != '#')
                    count++;
                left--;
                right++;
            }
        }
        printf("%d
", count);
    }
    return 0;
}