• hdu 1563 Find your present!


    Find your present!

    Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3579    Accepted Submission(s): 2386

    Problem Description
    In the new year party, everybody will get a "special present".Now it's your turn to get your special present, a lot of presents now putting on the desk, and only one of them will be yours.Each present has a card number on it, and your present's card number will be the one that different from all the others.For example, there are 5 present, and their card numbers are 1, 2, 3, 2, 1.so your present will be the one with the card number of 3, because 3 is the number that different from all the others.
     
    Input
    The input file will consist of several cases.   Each case will be presented by an integer n (1<=n<=200, and n is odd) at first. Following that, n positive integers will be given in a line. These numbers indicate the card numbers of the presents.n = 0 ends the input.
     
    Output
    For each case, output an integer in a line, which is the card number of your present.
     
    Sample Input
    5
    1 1 3 2 2
    3
    1 2 1
    0
     
    Sample Output
    3
    2
    位运算:
     1 #include <iostream>
     2 using namespace std;
     3 
     4 int main(){
     5     int n, num;
     6     while(cin >> n && n != 0){
     7         int ans = 0;
     8         for(int i = 0; i < n; i++){
     9             cin >> num;
    10             ans = ans ^ num;
    11         }
    12         cout << ans << endl;    
    13     }
    14     return 0;
    15 }
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  • 原文地址:https://www.cnblogs.com/qinduanyinghua/p/5560600.html
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