Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
1 class Solution { 2 public: 3 void sortColors(vector<int>& nums) { 4 int i = 0, j = 0, k = nums.size() - 1; 5 while (j <= k) { 6 if (nums[j] == 0) { 7 swap(nums[i++], nums[j++]); 8 } else if (nums[j] == 2) { 9 swap(nums[k--], nums[j]); 10 } else { 11 j++; 12 } 13 } 14 } 15 };