Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
/** * Definition for singly-linked list. * class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public boolean hasCycle(ListNode head) { //双指针,一快一慢,绝对速度为1,如果相遇 有环,马上返回,fast==null或者fast为尾节点时,返回false if(head==null) return false; ListNode fast=head; ListNode slow=head; while(fast!=null&&fast.next!=null){ fast=fast.next.next; slow=slow.next; if(fast==slow) return true; } return false; } }