• 签到功能实现


    1. 需求分析

    签到可以获得积分,礼券,小样,正品等

    连续签到,需要显示给用户,已经连续签到多少天

    若中断签到,从中断后的第一天签到时间,开始计算签到时间

    有没有补签功能

    展示签到的历史,显示该会员已经连续签到多少天

    签到对于时间的精确度要求比较高,当天签到的,那么记录的签到时间是当天,如果还有后续的一系列操作,比如计算积分,那后续操作的时间必须和签到的时间一致

    对于凌晨,跨天之类的场景,特别需要注意

    2.表结构设计

    会员表,积分表,是以前就有的,本次新增签到功能,需要新增一下的表:

    首先要有记录用户签到,暂且定义为HSignIn

     

    3. 后台代码实现

    Controller

    @RestController
    @RequestMapping(value = "signIn")
    public class SignController extends BaseController {
    
        @Autowired
        SignInService signInService;
    
        @Autowired
        SocialProviderService socialProviderService;
    
        @ApiOperation(value = "签到历史记录查询", notes = "签到历史记录查询")
        @GetMapping(value = "history", produces = {MediaType.APPLICATION_JSON_UTF8_VALUE})
        private ResponseBean signHis(@RequestParam("userId") String userId,
                                          @RequestParam("social") String social) {
    
            ResponseBean responseBean = new ResponseBean();
            SignInHisResponse signInHisResponse = signInService.getSignInRecord(userId, social);
            responseBean.setData(signInHisResponse);
            return responseBean;
        }
        
        
        @ApiOperation(value = "天猫签到", notes = "天猫签到")
        @GetMapping(value = "signInTmallByJasmine", produces = {MediaType.APPLICATION_JSON_UTF8_VALUE})
        private ResponseBean signInTmallByJasmine(@RequestParam("userId") String userId,
                                                  @RequestParam("time") Long time,
                                         @RequestParam("social") String social) {
            ResponseBean responseBean = new ResponseBean();
            SignInHisResponse signInHisResponse = signInService.tmallSignInWithTime(userId, social,time);
            responseBean.setData(signInHisResponse);
            return responseBean;
        }
        
    }
    

    具体实现:

    连续签到,今日是否已经签到 ===方法判断

    private static int getContinuousSignInDay(
    			List<HTmallSignInRecord> signInList) {
    		// continuousDay 连续签到数
    		int continuousDay = 1;
    		boolean todaySignIn = false;
    		Date today = new Date();
    		for (int i = 0; i < signInList.size(); i++) {
    			HTmallSignInRecord signIn = signInList.get(i);
    			int intervalDay = distanceDay(today, signIn.getSignDT());
    			// 当天签到
    			if (intervalDay == 0 && i == 0) {
    				todaySignIn = true;
    			} else if (intervalDay == continuousDay) {
    				continuousDay++;
    			} else {
    				// 不连续,终止判断
    				break;
    			}
    		}
    		if (!todaySignIn) {
    			continuousDay--;
    		}
    		return continuousDay;
    	}
    
    	/**
    	 * 两个日期对比间隔天数
    	 *
    	 * @param smallDay
    	 * @return boolean
    	 * @Param largeDay
    	 **/
    	private static int distanceDay(Date largeDay, Date smallDay) {
    		int day = (int) ((largeDay.getTime() - smallDay.getTime()) / (1000 * 60 * 60 * 24));
    		return day;
    	}
    

      

    签到相关的接口

    public interface SignInService {
    
    	SignInHisResponse getSignInRecord(String userId, String social);
    
    	SignInHisResponse tmallSignIn(String userId, String social);
    
    	SignInHisResponse tmallSignInWithTime(String userId, String social,Long time);
    	
    }
    

     

    和具体的实现

    @Service
    public class SignInServiceImpl implements SignInService {
    
    	@Autowired
    	HTmallSignMapper hTmallSignMapper;
    
    	@Autowired
    	SocialService socialService;
    
    	@Autowired
    	SocialProviderService socialProviderService;
    
    	@Autowired
    	BCustomerService bCustomerService;
    
    	@Autowired
    	PEService peService;
    
    	@Autowired
    	CustomerService customerService;
    
    	@Autowired
    	SendMemberInfoToEcrmMqTask sendMemberInfoToEcrmMqTask;
    
    	@Value("${sys.name}")
    	private String sysName;
    
    	@Value("${pe.event.signIn.tmall}")
    	String tmallSignInPeEventCode;
    
    	@Override
    	public SignInHisResponse getSignInRecord(String userId, String social) {
    		int cstId = socialService.findCstIdBySocialAndSocialId(userId, social);
    		SignInHisResponse signInHisResponse = new SignInHisResponse();
    		List<HTmallSignInRecord> tlist = hTmallSignMapper.getTmallSignRecords(cstId);
    		signInHisResponse.setAlreadySignInTodayFlag((hTmallSignMapper.getSignInToday(cstId) > 0) ? true : false);
    		if (null != tlist && tlist.size() > 0) {
    			signInHisResponse.setTmallSignInRecords(tlist);
    			signInHisResponse
    					.setContinuousSignInDay(getContinuousSignInDay(tlist));
    		}
    		return signInHisResponse;
    	}
    
    	
    
    	@Override
    	public SignInHisResponse tmallSignInWithTime(String userId, String social, Long time) {
    		Date date = new Date(time);
    		SimpleDateFormat sd = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
    		String tt =sd.format(date);
    		int cstId = socialService.findCstIdBySocialAndSocialId(userId, social);
    		SignInHisResponse signInHisResponse = new SignInHisResponse();
    		// 今天是否已签到
    		if (hTmallSignMapper.getSignInThisDay(cstId,tt) > 0){
    			System.out.println("今日已经签到");
    		List<HTmallSignInRecord> tlist = hTmallSignMapper.getTmallSignRecords(cstId);
    		signInHisResponse.setTmallSignInRecords(tlist);
    		return signInHisResponse;}
    		else {
    
    			// 开始签到
    			Boolean result = hTmallSignMapper.insertSignInRecord4ThisDay(cstId, tt);
    			if (result) {
    				List<HTmallSignInRecord> tlist = hTmallSignMapper.getTmallSignRecords(cstId);
    				signInHisResponse.setAlreadySignInTodayFlag((hTmallSignMapper.getSignInToday(cstId) > 0) ? true : false);
    				signInHisResponse.setContinuousSignInDay(getContinuousSignInDay(tlist));
    				signInHisResponse.setTmallSignInRecords(tlist);
    				try {
    					peService.sendEventWithTime(cstId, sysName, tmallSignInPeEventCode, time);
    				} catch (Exception e) {
    					// TODO Auto-generated catch block
    					e.printStackTrace();
    				}
    				sendMemberInfoToEcrmMqTask.syncMemberInfoToECRM(cstId,tmallSignInPeEventCode);
    			}
    
    			return signInHisResponse;
    		}
    	}
    }
    

      

     

      

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  • 原文地址:https://www.cnblogs.com/qianjinyan/p/11423772.html
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